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garri49 [273]
3 years ago
6

Octagon ABCDEFGH and its dilation, octagon A'B'C'D'E'F'G'H', are shown on the coordinate plane below:

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer: The answer is (c) \dfrac{1}{2}.

Step-by-step explanation: We are given the dilation of octagon ABCDEFGH which forms the octagon A'B'C'D'E'F'G'H' as shown in the given figure. Origin is the centre of dilation. We are to find the scale factor of the dilation.

We know that, to find the scale factor, we need to divide the length of one side of the dilated octagon A'B'C'D'E'F'G'H' by the length of the corresponding side of the original octagon ABCDEFGH.

Also, from the figure, we note that

GH = 4 units and G'H' = 2 units.

Therefore, the scale factor will be

S=\dfrac{G'H'}{GH}=\dfrac{2}{4}=\dfrac{1}{2}.

Thus, (c) is the correct option.

choli [55]3 years ago
3 0
We can take out one of the points such as H (2,6) and then take it's dilation H' (1,3)and see that 2 and 6 were both multiplied by 1/2 to get 1 and 3, so the scale factor is 1/2
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50 pts for this!!!
butalik [34]
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8 0
3 years ago
I need to find AB and DE​
MatroZZZ [7]

Answer:

AB = 21 and DE = 23

Step-by-step explanation:

Given 2 intersecting chords inside the circle then

The products of the measures of the parts of one chord is equal to the products of the measures of the parts of the other chord, that is

x(x + 13) = (x + 10)(x + 1) ← distribute parenthesis on both sides

x² + 13x = x² + 11x + 10 ← subtract x² + 11x from both sides

2x = 10 ( divide both sides by 2 )

x = 5

Hence

AB = x + 10 + x + 1 = 2x + 11 = (2 × 5) + 11 = 10 + 11 = 21

DE = x + x + 13 = 2x + 13 = (2 × 5) + 13 = 10 + 13 = 23

4 0
3 years ago
How many 4-digit numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 which are divisible by 5 when none of the digits a
Masja [62]

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120 4-digit numbers.

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= 6P3

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= 120.

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3 years ago
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