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stiks02 [169]
4 years ago
10

Lipid-soluble hormones usually bind to __________ receptors.

Chemistry
1 answer:
kumpel [21]4 years ago
3 0

Answer:...intercellular receptors

Explanation:

Lipophilic hormone also known as lipid-soluble hormones can pass through the cell's plasma membrane, to bind to intracellular receptors, so as to effect change in gene expression.

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What is the correct order for the development of the atomic model
tensa zangetsu [6.8K]

Answer: I think it's A. C-A-D-B

Explanation:

John Dalton's theory was publicized in 1803

J.J Thomson's theory was publicized in 1904

Ernest Rutherford's theory was publicized in 1911

And Neil Bohr's was publicized in 1926

3 0
4 years ago
2 SO2(g) + O2(g) 2 SO3(g) Assume that Kc = 0.0680 for the gas phase reaction above. Calculate the corresponding value of Kp for
son4ous [18]

Answer: The corresponding value of K_p for this reaction at 84.5°C is 0.00232

Explanation:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

Relation of with is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

= equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 0.0680

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature  =84.5^0C=(273+84.5)K=357.5K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=0.0680\times (0.0821\times 357.5)^{-1}\\\\K_p=0.00232

Thus the corresponding value of K_p for this reaction at 84.5°C is 0.00232

6 0
3 years ago
Science 9- Bohr models worksheet
icang [17]

Answer:

What do u mean

Explanation:

6 0
4 years ago
Example 1: Calculate the concentration of NaOH
docker41 [41]

Answer:

2.4 %

Explanation:

.15 mole  *  ( 23 + 16 + 1) gm / mole =  6 gm in solution

  250 cm^3 of water solvent weighs  250 gm

6 gm / 250 gm = 2.4 %

6 0
2 years ago
Read 2 more answers
Deduce the charge on the dichromate ion in Ag2Cr2O7. <br>The charge on a silver ion is +1 .​
Ivenika [448]

Answer:

2-

Explanation:

The dichromate ion is the part of the compound that looks like: Cr2O7.

Our current compound is Ag2CrO7. The “2” on Ag indicates that there are two atoms of Ag in this compound, while the absence of a number on Cr2O7 indicates that there is only one atom of Cr2O7.

In order to maintain balance within the compound, the product of one of the ion’s charge with its atom amount must be equivalent to the product of the other ion’s charge with its atom amount. This is because the charges will ultimately add up to 0, which is the neutral substance we want.

Here, we know the “atom amount” of Ag is 2 and that its charge is 1+. So that’s 2 * 1 = 2. We also know that the “atom amount” of Cr2O7 is 1 and that its charge is x, for example. Then: x * 1 + 2 = 0. That means x = -2.

Thus, the charge on the dichromate ion is 2-.

6 0
3 years ago
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