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allochka39001 [22]
4 years ago
5

A Buffer Solution is 0.100 M in both HC7H5O2 and LiC7H5O2 and has a pH of 4.19. Which of the following pH values would you expec

t from the addition of a small amount of a dilute solution of a strong base?
- 3.89
- 3.69
- 5.69
- 4.49
- There is not enough information.
Chemistry
1 answer:
luda_lava [24]4 years ago
7 0

Answer: Nov 24, 2010 · A buffer solution is 0.100 M in both HC7H5O2 and LiC7H5O2 and has a pH of 4.19. Which of the following pH values would you expect from the addition of a small amount of a dilute solution of a strong base? A. 4.49 B.3.89 C.5.69 D. 3.69 E. There is not enough info to determine

A 1.0L buffer solution contains 0.100 mol of HC2H3O2 and 0 ...

Mar 29, 2016

A 1.00 L buffer solution is 0.250 M in HF and 0.250 M in ...

Jul 05, 2011

Explanation:

You might be interested in
Indicate which solution in each pair has the lower pH. Your response should be a four letter "word". The first letter should be
JulijaS [17]

Answer:

bcfh

Explanation:

HClO₄ reacts with water thus:

HClO₄ + H₂O → H₃O⁺ + ClO₄⁻

That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:

b) 0.2 M HClO4

The reaction of NaClO₄ is:

NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺

The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:

<em>c) 0.1 M NaClO or</em>

HF reacts with water thus;

HF ⇄ H⁺ + F⁻

The equilibrium constant is:

k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴

For HNO₂ equilibrium is:

HNO₂ ⇄ H⁺ + NO₂⁻

k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴

As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.

f) 0.1 M HNO2

NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:

h) pure water

I hope it helps!

7 0
4 years ago
You add 28 grams of carbon. You find the actual yield to be 181.2 grams of CO2. What is the percent yield of CO2?
liraira [26]

Answer:

79.14%

Explanation:

Given the equation : 2Fe2O3 + 3C 4Fe + 3C02

The theoretical yield of CO2 ; is 102.6g

Actual yield = 81.2 gram

Percentage yield = (actual yield / theoretical yield) * 100%

Percentage yield = (81.2 / 102.6) * 100%

Percentage yield = 0.7914230 * 100%

Percentage yield = 79.14%

Hence, tbe percentage yield of CO2 is 79.14%

4 0
3 years ago
A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )
Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = \frac{0.1200}{1000}\times 50.0 moles = 0.00600 moles

Neutralization reaction (back titration): NaOH+HCl\rightarrow NaCl+H_{2}O

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0
3 years ago
How many grams would be in 4.45 x 10^23 molecules of N203
SVETLANKA909090 [29]

Answer:

56.24g

Explanation:

To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).

number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23

n = 4.45/6.02 × 10^(23 - 23)

n = 0.74 × 10^0

n = 0.74moles.

Using the formula below to find the mass of N2O3;

mole = mass ÷ molar mass

Molar mass of N2O3 = 14(2) + 16(3)

= 28 + 48

= 76g/mol

mass = mole × molar mass

Mass = 0.74 × 76

Mass = 56.24g

3 0
3 years ago
What kind of value does biodiversity have within an ecosystem?
german

Answer:

A. Ecological value

Explanation:

3 0
3 years ago
Read 2 more answers
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