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3 years ago

Just need help on this one

Chemistry

2 answers:

lys-0071 [83]3 years ago

7 0

Answer:

2Cs+Sr(CrO4)-->Cs2(CrO4)+Sr

Explanation:

just set them equal, only value that changed was the amount of cesium(Cs)

expeople1 [14]3 years ago

5 0

Answer:

A, 2 ,1, 1, 1

Explanation

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What me with this work sheet plllzz

Brut [27]

Answer:

The answer for 17 is maybe

8 0

3 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago

Which of the following is an element water oxygen carbon dioxide ammonia

Makovka662 [10]

Oxygen is the only element in that list, the rest are compounds.

8 0

4 years ago

The delocalized cloud of π electrons in benzene is formed by the overlap of 6 ________ orbitals.

Radda [10]

The delocalized cloud of π electrons in benzene is formed by the overlap of 6 p-orbitals.

So, option B is correct one.

In the case of hydrocarbons, delocalisation occurs in benzene rings , where a hexagon of six carbon atoms has decalized electrons spread over the whole ring.

All of the carbon atoms in the benzene rings are $sp^{2}$ orbitals around the ring produces a framework of six sigma bonds, while the unhybridized p-orbitals which are perpendicular to this plane over in side-to-side fashion to form three pi-bonds.

To learn more about benzene

brainly.com/question/14525517

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8 0

2 years ago

What is the number of atoms contained in 500. grams of carbon?

jolli1 [7]

Somewhere around 2500. hope this helps!

6 0

3 years ago