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swat32
3 years ago
13

Identify the Lewis acid in this balanced equation: Ag+ NH3 Ag(NH3)2+

Chemistry
2 answers:
Tanya [424]3 years ago
8 0

Answer: Ag+

Explanation: Just did it

irina [24]3 years ago
7 0

Answer:

Ag+

Explanation:

Just did it on edge

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Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?
dlinn [17]

Answer:

Reagent O₂ will be consumed first.

Explanation:

The balanced reaction between O₂ and C₄H₁₀ is:

2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles
  • O₂: 13 moles
  • CO₂: 8 moles
  • H₂O: 10 moles

Being:

  • C: 12 g/mole
  • H: 1 g/mole
  • O: 16 g/mole

The molar mass of the compounds that participate in the reaction is:

  • C₄H₁₀: 4*12 g/mole + 10*1 g/mole= 58 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • CO₂: 12 g/mole + 2*16 g/mole= 44 g/mole
  • H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles* 58 g/mole= 116 g
  • O₂: 13 moles* 32 g/mole= 416 g
  • CO₂: 8 moles* 44 g/mole= 352 g
  • H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10}   }{116 grams of C_{4}H_{10}}

mass of O₂= 223.78 grams

But 21.78 grams of O₂ are not available, 78.1 grams are available. Since you have less mass than you need to react with 62.4 g of C₄H₁₀, <u><em>reagent O₂ will be consumed first.</em></u>

3 0
3 years ago
How many moles of Fe are produced from 7 moles of Zn?<br> Zn(s) + FeSO4(aq) → ZnSO4(aq) + Fe(s)
guajiro [1.7K]

Answer:

7 mol Fe

General Formulas and Concepts:

<u>Chemistry</u>

  • Stoichiometry

Explanation:

<u>Step 1: Define</u>

RxN:     Zn (s) + FeSO₄ (aq) → ZnSO₄ (aq) + Fe (s)

Given:   7 moles Zn

<u>Step 2: Stoichiometry</u>

<u />7 \ mol \ Zn(\frac{1 \ mol \ Fe}{1 \ mol \ Zn} ) = 7 mol Fe

<u>Step 3: Check</u>

<em>We are given 1 sig fig.</em>

Since our final answer is in 1 sig fig, there is no need to round.

3 0
3 years ago
Does sauce either rhyme with avoid, crowd,false,hall,or hawk​
Alenkinab [10]

Answer:

false

Explanation:

the last letters in the words ryhme and make similiar sounds unlike the other words

7 0
3 years ago
If the reactants of wood when burning weigh 10 kgs, how much will the products weigh?
aksik [14]

Answer:

the weight of products is is equal the weight of the wood plus the weight of oxygen that was used to burn that wood, so weigh of the product is greater than 10 kilograms.

Explanation:

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are rearranged from the reactants to the products.

In this example wood (mostly carbon) and oxygen are reactants and carbon dioxide (mostly) is product of reaction.

7 0
3 years ago
A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of
goldenfox [79]

Answer:

108 kPa  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂             Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂      Divide each side by V₁

      p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?;                 V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the <em>pressure </em>

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)  

   = 122.2 kPa × 0.8542 × 1.0357

   = 108 kPa

4 0
3 years ago
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