Answer:
Explanation:
2Al + 3Cl2 --> 2AlCl3
Ag2O + Be -----> 2Ag + BeO
4K + O2 ---> 2K2O
CoP + 3NaBr ---> CoBr3 + Na3P
Si + Hg2S ---> SiS2 + Hg
6Li + Ni3N2 --- > 2Li3N + 3Ni
3Ca + 2K3N --> Ca3N2 + 6K
SnS2 + 2F2 --> SnF4 + 2S
Under the same conditions of temperature and pressure, a liquid differs from a gas because the particles of the liquid a) are in constant straight-line
Answer:
Therefore, the oxidation state of N in NaNO₂ is +3
Explanation:
Problem: calculating the oxidation state of nitrogen N in NaNO₂
let us denote the oxidation number of Nitrogen as N:
We know from the periodic table that Na has an oxidation number of +1 i.e it will readily want to lose 1 electron so as to complete its octet.
Oxygen is known to have an oxidation number of -2
Summation of the oxidation number of each atoms is 0 for neutral compound.
Therefore to calculate the oxidation state of Nitrogen in NaNO₂, we express as:
+1 + N + (-2 x 2) = 0
1 + N = 4
N = 4-1 = +3
Therefore, the oxidation state of N in NaNO₂ is +3
answer: its rate i might be wrong but i'm positively sure its right