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zalisa [80]
4 years ago
6

Calculate the half-life (in s) of a first-order reaction if the concentration of the reactant is 0.0576 M 17.1 s after the react

ion starts and is 0.0249 M 97.8 s after the reaction starts.
Chemistry
1 answer:
garik1379 [7]4 years ago
7 0

Answer:

66.7s

Explanation:

Let's bring out the parameters we were given...

Half life = ?

Initial Concentration = 0.0576 M

Final Concentration = 0.0249 M

Time for the concentration change to occur = 97.8s - 17.1s = 80.7s

Formular for half life (t1/2) is given as;

t1/2 = ln2 / k   ≈   0.693 / k

where k = rate constant

From the formular of first order reactions;

ln[A] = ln[A]o − kt

where [A] = Final Concentration and [A]o = Initial Concentration

Inserting the values, we have;

ln(0.0249) = ln(0.0576) - k(80.7)

Upon solving for k, we have;

-0.8387 = -k(80.7)

k = 0.01039 s−1

t1/2 = 0.693 / k = 0.693 / 0.01039 = 66.7s

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Archy [21]

Answer:

The answer is 139.1 g of sodium azide.

Explanation:

To solve this question we need to find first the stoichometry of the reaction to find the moles involved.

1. The balanced formula:

2NaN3 ⇒ 3N2 + 2Na

(important: the nitrogen is a gas, therefore, is always diatomic N2)

2. The moles:

We need to convert the 90 g of N2  into moles to know the relations of amounts between the other compounds in the chemical equation

90 g of N2 x (1 mol of N2/ 28 g of N2) = 3.21 mol of N2

3.  Stoichometry:

The relations of the amounts of moles of N2 and NaN3 using the balanced formula  

3.21 mol of N2 x (2 mol of NaN3/3 mol of N2) = 2.14 mol of NaN3

4. Moles into grams

then to answer the question we convert the moles value of NaN3 into grams of NaN3

2.14 mol of NaN3 x ( 65 g of NaN3/ 1 mol of NaN3) = 139.1 g of NaN3.

and this is the answer of the question.

5 0
4 years ago
A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the
guajiro [1.7K]

The question that will best help the student to classify the material is; "is the material malleable or ductile?"

Generally, materials can be classified as metals or non metals. There are properties that are particular to metals and there are properties that are particular to nonmetals and these properties can be used to identify each one of the materials.

The question that will best help the student to classify the material is; "is the material malleable or ductile?" These metallic properties.

Learn more:

brainly.com/question/1659592

Missing parts;

A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the student classify the material? A. Is the material malleable or ductile? B. Does the material feel hard to the touch? C. Will the material float in water? D. Does the material feel rough or smooth?

8 0
2 years ago
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Find the density of an empty tissue box with a mass of 345 grams and a volume of 1125 cm3.
trasher [3.6K]

Answer:

The answer is

<h2>0.307 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of box is 345 g

volume = 1125 cm³

The density of the object is

density =  \frac{345}{1125}  \\  = 0.3066666...

We have the final answer as

<h3>0.307 g/cm³</h3>

Hope this helps you

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3 years ago
What is ionization energy? What is fist ionization energy?
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Korvikt [17]

Answer:

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5 0
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