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Sergio [31]
3 years ago
12

Why does the golf tee fall into the bottle when the hoop is pulled

Physics
1 answer:
Artemon [7]3 years ago
6 0

Answer:

Gravity overcomes the hex nut's stationary inertia and moves the nut straight down into the bottle.

Explanation:

Hope this helps.

Have a good night ma´am/sir.

Be safe!

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What type of energy does a glow stick run on after it is cracked?
Maru [420]

Answer:

When you crack a glow stick, you break the glass inside. Its ingredients are then free to mix and react, releasing carbon dioxide and chemical energy, which is converted to visible light.

Explanation:

6 0
3 years ago
Two 6.7 kg bodies, A and B, collide. The velocities before the collision are and . After the collision, . What are (a) the x-com
Law Incorporation [45]

Question:

Two 6.7 kg bodies, A and B, collide. The velocities before the collision are 40i+37j and 19 i +3.7 j . After the collision 9.8 i + 5.1 j, 50 i+35.6 j . What are (a) the x-component and (b) the y-component of the final velocity of B? (c) What is the change in the total kinetic energy (including sign)?

Answer:

(a) 50 m/s

(b) 35.6 m/s

(c) -735.16 J

Explanation:

Given,

u_A=40i+37j=\sqrt{40^2+37^2}=54.5 m/s

u_B=19 i +3.7 j=\sqrt{19^2+3.7^2}=19.4m/s

v_A=9.8 i + 5.1 j=\sqrt{9.8^2+5.1^2}=11m/s

v_B=50 i+35.6 j=\sqrt{50^2+35.6^2}=61.4m/s

Change in kinetic energy = final kinetic energy - initial kinetic energy

\Delta K.E.=\frac{1}{2} m(v_A+v_B)^2 -\frac{1}{2} m(u_A+u_B)^2\\

\Delta K.E.=\frac{1}{2} 6.7(11+61.4)^2 -\frac{1}{2} 6.7(54.5+19.4)^2\\\Delta K.E. =17559.89-18295.05\\\Delta K.E. = -735.16 J

7 0
3 years ago
13. A hiker walks 200 m west and then walks 100 m north. In what direction is her resulting displacement?
prohojiy [21]
100m north west   is the answer                                      
4 0
3 years ago
Read 2 more answers
When an electron is removed from a neutral atom, it becomes....
inessss [21]

Answer:

A

Explanation:

7 0
4 years ago
Read the scenario.
Fofino [41]

Answer:

displacement = 2 m west

Explanation:

The displacement of an object is a vector connecting the final point of the motion of the object to the initial point, and its magnitude is equal to the length of the vector. So the magnitude of the displacement is basically the distance (measured in a straight line) between the final point and the starting point.

In this problem, we have:

- initial position of the acorn: 0 m

- final position of the acorn: 2 m west

So, the displacement has a magnitude of

d = 2 m - 0 m = 2 m

And the direction is west, since the final position is west compared to the initial position.

5 0
4 years ago
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