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Ira Lisetskai [31]
3 years ago
13

An environmental scientist performs research to discover what is in the solid

Physics
2 answers:
xxMikexx [17]3 years ago
8 0

Answer:

D i took the test

Explanation:

Sholpan [36]3 years ago
8 0

Answer:

The answer is D.

Explanation:

The other ones just don't make sense. AT ALLLLLL!!!!!!!!!!!!!!!!!!!!!!!

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A caris initially at rest starts moving with a constant acceleration of 0.5 m/s2 and travels a distance of 5 m. Find
EleoNora [17]

Answer:

(I)

{ \bf{ {v}^{2} =  {u}^{2}  - 2as }} \\  {v}^{2}  =  {0}^{2}  - (2 \times 0.5 \times 5) \\  {v}^{2}  = 5 \\ { \tt{final \: velocity = 2.24 \:  {ms}^{ - 1} }}

(ii)

{ \bf{v = u + at}} \\ 2.24 = 0 + (0.5t) \\ { \tt{time = 4.48 \: seconds}}

8 0
3 years ago
Which term refers to a variable that a scientist adjusts during an experiment
vladimir1956 [14]

Responding variable

Explanation:

7 0
3 years ago
Read 2 more answers
1 the life cycle of a star begins with a cloud of gas and dust called a
pogonyaev
The answer is Nebula
5 0
3 years ago
You want to build a search light. The search light is to have an outgoing parallel beam. You have a small, very bright light (a
andrew11 [14]

Answer:

1 m                              

Explanation:

Given

The mirror is a concave mirror.

Radius of curvature = 2 m

Now, for a parallel beam after reflection  occurs, the object should be placed at the focus of the mirror.

We know, focal length = radius of curvature / 2

                                      = 2 / 2

                                      = 1

Thus the focal length is 1 m.

Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.

3 0
3 years ago
If the period of a clock signal is 500 ps, the frequency is:_____
NNADVOKAT [17]

Answer:

The frequency of the signal is 2 GHz

Explanation:

Given;

period of the clock signal, T = 500 ps = 500 x 10⁻¹² s

the frequency of the signal is given by;

F= \frac{1}{T}\\\\F = \frac{1}{500*10^{-12}}\\\\F = 2*10^{9} \ Hz

F = 2 GHz

Therefore, the frequency of the signal is 2 x 10⁹ Hz or 2 GHz

4 0
4 years ago
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