Answer:
1 m
Explanation:
Given
The mirror is a concave mirror.
Radius of curvature = 2 m
Now, for a parallel beam after reflection occurs, the object should be placed at the focus of the mirror.
We know, focal length = radius of curvature / 2
= 2 / 2
= 1
Thus the focal length is 1 m.
Hence the object should be placed at 1 m from the concave mirror for parallel beam reflection.
Answer:
The frequency of the signal is 2 GHz
Explanation:
Given;
period of the clock signal, T = 500 ps = 500 x 10⁻¹² s
the frequency of the signal is given by;

F = 2 GHz
Therefore, the frequency of the signal is 2 x 10⁹ Hz or 2 GHz