I believe it would be x because you are trying to find the width of the wave but i could be wrong
16,000 m/s
Since it’s speed, and the distance is unknown. Gravity isn’t applying a noticeable force too on the rocket, as if it were, then the rocket would be accelerating negatively.
Answer:
96.21 ft/s
Explanation:
To solve this, you only need to use one expression which is:
Vf² = Vo² + 2gh
g = 9.8 m/s²
However, this exercise is talking in feet, so convert the gravity to feet first:
g = 9.8 * 3.28 = 32.15 ft/s²
Vo is zero, because it's a free fall and in free fall the innitial speed is always zero. With this, let's calculate the speed at 2 seconds, with a height of 64 ft, and then with the 256 ft:
V1 = √2*32.15*64
V1 = 64.15 ft/s
V2 = √2*32.15*256
V2 = 128.3 ft/s
So the average rate is:
V = 128.3 + 64.15 / 2
V = 96.22 ft/s
Answer:
1.43m
Explanation:
Given data
m1= 50kg
m2=70kg
We are told that Sally m1= 50 sat at one end which is 2m from the center
Hence, the summation of clockwise moment = summation of anticlockwise moment
See the attached image for your reference
50*2= 70*x
100= 70x
x= 100/70
x=1.43m
Hence the mass m2 will be at the 1.43m mark for the net torque to be zero
Answer:
9.8 m/s/s, for earth 1.7 N on the Moon.
Explanation:
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