As we know that the formula of kinetic energy will be
now here we know that
m = 2 kg
v = 1 m/s
so from the above equation we have
A 4.10 g bullet moving at 837 m/s strikes a 820 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
1 answer:
You might be interested in
Answer:
A.The spring constant for B is one quarter of the spring constant for A.
Explanation:
If spring A oscillates at twice the frequency of spring B, and period is frequency inverted. It means spring B has a period twice of spring A's.
As , and the 2 springs have the same mass
So A.The spring constant for B is one quarter of the spring constant for A. is the correct answer.
Answer:
0.37 m
Explanation:
The angular frequency, ω, of a loaded spring is related to the period, T, by
The maximum velocity of the oscillation occurs at the equilibrium point and is given by
A is the amplitude or maximum displacement from the equilibrium.
From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,
To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation
is the final velocity,
is the initial velocity (same as v above), a is acceleration of gravity and h is the height.