Answer:
The sum is 2275
Step-by-step explanation:
Given
Required
The sum
Using arithmetic progression, we have:
Where:
--- first term
--- last term
So, we have:
Answer:
I keep getting no solution
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
5(x−4)=−9+5x+15
(5)(x)+(5)(−4)=−9+5x+15(Distribute)
5x+−20=−9+5x+15
5x−20=(5x)+(−9+15)(Combine Like Terms)
5x−20=5x+6
5x−20=5x+6
Step 2: Subtract 5x from both sides.
5x−20−5x=5x+6−5x
−20=6
Step 3: Add 20 to both sides.
−20+20=6+20
0=26
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:
s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number
Here you are given a=10 and r=1/5 so your equation is:
s(n)=10(1-(1/5)^n)/(1-1/5) let's simplify this a bit:
s(n)=10(1-(1/5)^n)/(4/5)
s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:
s(5)=12.5(1-(1/5)^5)
s(5)=12.496
as an improper fraction:
(125/10)(3124/3125)
390500/31240
1775/142
Just look at the pic. U need to have the y-intercept at -1. From there you go down 4 and to the right one and plot the point.
Answer: (a) 11.8
(b) 13
Step-by-step explanation:
Since George wants to put a string of lights around , it means we will have to consider the perimeter of the shape.
Perimeter of a rectangle is given by :
P = 2( L+B)
P = 2 ( 2.5 + 3.4)
P = 2 ( 5.9)
P = 11.8 meters
(b) Since he wants to put an addition to his wooden deck that is 0.6 meters longer , then the perimeter will be the perimeter of the first shape + 2(0.6). We used 2(0.6) because the two lengths of the rectangle must be considered
Therefore, we have
P = 11.8 meters + 2(0.6)
= 11. 8 + 1.2
= 13 meters
Therefore George needs 13 meters length of light
