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fiasKO [112]
3 years ago
15

The triangular entrance to a tent is 2/3 as wide as it is tall. The area of the entrance is 12ft^2. Find the height and the base

.
Mathematics
1 answer:
Reika [66]3 years ago
4 0
X+\frac{2}{3} x=12
5x=36
x=7.2
So, the triangular entrance to the tent is 7.2 feet tall and 4.8 feet wide
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Six more than 1/5 a number is 12. What is the number
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Answer:

Step-by-step explanation:

let x be the number

6+1/5x=12

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2 years ago
Work out the area of a circle with a radius 6.2cm, take n/pi to be 3.142 and give your answer to 2 decimal places.
s344n2d4d5 [400]

Answer:

Step-by-step explanation:

Area is pi times r squared.  I don't know how to write that on the keyboard.  Take your pi(3.142) times the radius(6.2)squared.  Pemdas tell us to do exponents first, so 6.2 squared is 38.44.  To square a number, just multiply it times itself.  So now, we have pi(3.142) times the squared radius(38.44).  So, 3.142X38.44=

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3 0
3 years ago
Pls help ill give points
Dafna1 [17]

I hope you don't find the solution too messy. If there is anything you don't get. Let me know and I will explain it:


6 0
3 years ago
Help ASAP! 20 Points!
ANTONII [103]

Volume of cylinder is 3 times of volume of cone having same base diameter and same height.

<u>Solution:</u>

Given that  

A cylinder and A cone have the same diameter = 10 inches and same height = 12 inches

Need to find the relationship between volume of cylinder and cone.

Let’s calculate volume of each object separately first.

<em><u>Calculation of volume of cylinder :</u></em>

Formula of volume of cylinder is given as:

V_{c y}=\pi r^{2} h

Where π=3.14

\text { radius } r=\frac{\text {diameter}}{2}=\frac{10}{2}=5 \text { inches }

height h = 12 inches  

On substituting given values in formula of cylinder we get

\begin{array}{l}{V_{c y}=3.14 \times 5^{2} \times 12=942 \text { cubic inches }} \\\\ {\text { Volume of cylinder }=V_{c y}=942 \text { cubic inches }}\end{array}

<em><u>Calculation of volume of cone:</u></em>

Formula of volume of cone is given as:

V_{c o}=\frac{\pi r^{2} h}{3}

Here π=3.14

\begin{array}{l}{\text { radius } r=\frac{\text { diameter }}{2}=\frac{10}{2}=5 \text { inches }} \\\\ {\text { height } \mathrm{h}=12 \text { inches }}\end{array}

On substituting given values in formula of cone we get

V_{c o}=\frac{3.14 \times 5^{2} \times 12}{3}=314 \text { cubic inches }

\text { Volume of cone }=V_{c o}=314 \text { cubic inches }

On comparing the two volumes we get  

V c y: V c o=942: 314=3: 1

Hence can conclude that Volume of cylinder is 3 times of volume of cone having same base diameter and same height.

8 0
3 years ago
2*2<br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28300%29%20" id="TexFormula1" title=" \cos(300) " alt=" \cos(300) " align="ab
ankoles [38]

Step-by-step explanation:

\cos(300 \degree)  \\  \\  = \cos(360 \degree - 60\degree)  \\  \\  = \cos( 60\degree) \\  \\  =  \frac{1}{2}  \\  \\  \huge \orange{ \boxed{ \therefore \: \cos(300 \degree)  = \frac{1}{2}  }}

7 0
3 years ago
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