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Black_prince [1.1K]
4 years ago
9

Why is HCl considered a strong acid?

Chemistry
2 answers:
melomori [17]4 years ago
5 0
Hydrochloric acid<span> is in fact a </span>strong acid<span>. </span>Strong acids<span> are </span>strong<span> electrolytes, which, for most purposes, and they are assumed to ionize completely in water. </span>HClionizes completely to hydrogen ions, H+<span> and chloride ions, Cl</span>-<span>. ... but don't forget that weak </span>acids<span> only partially ionize in water.</span>
weqwewe [10]4 years ago
3 0
Because it feels good when that soothing feeling comes from it flowing through 
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If 20.0g of water at 56.2℃ absorbs 195 J of heat, what is the final temperature? *
Gnom [1K]

Answer

Explanation:

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3 0
3 years ago
Which of the following natural hazards occur for a long period of time?
saul85 [17]

Answer:

drought

Explanation:

droughts are long periods without water

3 0
3 years ago
You are given the following information: mass = 48 g; volume=24 cm. What is the density of this substance?
GaryK [48]

Answer:

Density = 0.0035 g/cm³

Explanation:

The density equation looks like this:

Density (g/cm³) = mass (g) / volume (cm³)

You have been given both the mass and volume. However, the given volume is not in the correct units. To convert cm to cm³, you should simply raise the given volume to the power of 3.

24 cm  =  (24 cm)³  =  24³cm³  =  13,834 cm³

Now, you can plug you mass and volume into the equation and solve for density. The final answer should have 2 sig figs to reflect the given values.

Density = mass / volume

Density = 48 g / 13,824 cm³

Density = 0.00347 g/cm³

Density = 0.0035 g/cm³

6 0
2 years ago
Give the electronic configuration of carbon atom.​
zimovet [89]

Answer:

1s2 2s2 2p2

Explanation:

it has 6 electrons in two energy levels so the sub levels are 1s, 2s and 2p

4 0
3 years ago
A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
4 years ago
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