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Nina [5.8K]
3 years ago
15

What mass of oxygen is required to completely react with 2 moles of ch4

Chemistry
1 answer:
Firlakuza [10]3 years ago
7 0
The balanced reaction that describes the reaction between methane and oxygen to produce water and carbon dioxide is expressed CH4  + 2 O2 = CO2 +2H2O. Hence for 2 moles of methane used, 4 moles of oxygen are needed to react completely.
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maw [93]

Answer:

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How many atoms are in 58.93 grams of cobalt (Co)?
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If you have 58.93g of Co it means that you only have 1 mol (use a periodic table to find the answer, if you had more find it by proportion, it's easier). 
There's 6.022 x 10^23 atoms per mol so you have 6.022 x 10^23 atoms of Co.
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7 0
3 years ago
The substances that are produced after the chemical reaction are called the ___​
sertanlavr [38]

Answer:

Products

Explanation:

During a chemical reaction, there are the reactants (left side), and the products (right side).

6 0
2 years ago
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Calculate AH for the reaction:<br> 2N2 (g) + 6H20 (g) → 302 (g) + 4NH3(g)
Ratling [72]

Answer:

Explanation:

4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)

ΔH_r={\sum}{ \Delta }H_f(\text{product})-{\sum}{ \Delta }H_f(\text{reactant})

ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f​ (NH 3 (g))+3ΔH f (O 2 (g)))

ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186

ΔH rex =−1532kJ/mol

Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.

7 0
2 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
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