Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
<h3>
Reaction between oxygen and ethene</h3>
Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.
C₂H₄ + 3O₂ ----- > 2CO₂ + 2H₂O
from the equation above;
3 moles of O₂ ---------> 2(18 g) of water
3.5 moles of O₂ ----------> x
![x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2} ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]](https://tex.z-dn.net/?f=x%20%3D%203.2%20%5Ctimes%20%5B%5Cfrac%7B2%20%5C%20moles%20%5C%20H_2O%7D%7B3%20%5C%20moles%20%5C%20O_2%7D%20%20%5D%20%5Ctimes%5B%20%5Cfrac%7B18.02%20%5C%20g%20%5C%20H_2O%7D%7B1%20%5C%20mole%20%5C%20H_2O%7D%20%5D)
Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
Learn more about reaction of ethene here: brainly.com/question/4282233
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Answer:Yes I am very good at acid
Explanation:
To determine whether the crown was made of pure gold or not, we need to compare the density of gold (19.3 g/mL) to the density of the crown.
The formula for density is
we know the mass of the crown is 714 grams and its volume is 38.3 mL. (Because it displaces 38.3 mL of water)
Using this information, we can plug the numbers into our density formula to solve for the density of the crown.
The density of the crown is 18.6 g/mL, thus the crown was not made of pure gold, as that has a density of 19.3 g/mL. In conclusion, the goldsmith tried to screw over the king.
1/8 got it from Yahoo answers and the answer was highlighted with 4 likes.... so most likely thats it
Only in case if there are impurities are present in other sample of that substance.
