Answer:
Option C. 
Step-by-step explanation:
we know that
If a system of two linear equations has an infinite number of solutions, then both equations must be identical
The given equation is

<u><em>Verify each case</em></u>
Option A. we have

apply distributive property

Compare with the given equation

Option B. we have

remove the parenthesis

Compare with the given equation

Option C. we have

apply distributive property

Compare with the given equation

therefore
This equation with the given equation form a system that has an infinite number of solutions
Option D. we have

Compare with the given equation

Answer:
C. I can’t really enter square roots
Step-by-step explanation:
a^2/3 = a^2*a^1/3
Which is the cube root of a squared
Answer:
g(x) = x^2 + 4x + 4
Step-by-step explanation:
In translation of functions, adding a constant to the domain values (x) of a function will move the graph to the left, while subtracting from the input of the function will move the graph to the right.
Given the function;
f(x) = x2 - 6x + 9
a shift 5 units to the left implies that we shall be adding the constant 5 to the x values of the function;
g(x) = f(x+5)
g(x) = (x+5)^2 - 6(x+5) + 9
g(x) = x^2 + 10x + 25 - 6x -30 + 9
g(x) = x^2 + 4x + 4
Answer:
x = 1 or x = 3 / 2 or x = −5 or x = 1 / 3
Refer the attachment for steps
Hope it helps
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A=pi r^2
= 20.25 pi is the answer