Answer: 500 investigated @ 12%, 1,000 @ 13%, 1,500 @ 14%. Process: Suppose $x investigated at 12%, $y @ 13%, $(x+y) @ 14%. According to the question we can set up the equations: x+y+x+y=3000 0.12x+0.13y+0.14(x+y)=400 Solve it: x=500, y=1,000. So x+y=1,500.
The mean of the sample given by 44,22,11,17,21 will be given by: the sum of x's will be: 44+22+11+17+21 =115 n=5 therefore the mean will be: μ=115/5 =23