Answer:
(a) E = 3.065 * 10^21 N/C
(b) The direction is radially outward.
Explanation:
Parameters given:
Number of protons = 94
Charge of proton = 1.6023 * 10^-19 C
Radius of nucleus = 6.65 fm = 6.65 * 10^-15
At the surface of the nucleus, Electric field, E is given as:
E = kq/r^2
Where k = Coulombs constant
r = radius of nucleus
=> E = (9 * 10^9 * 94* 1.6023 * 10^-19)/(6.65 * 10^21)
E = 3.065 * 10^21 N/C
The direction of the field is radially outward.