Answer:
The z-component of the force is 
Explanation:
From the question we are told that
The charge on the particle is 
The magnitude of the magnetic field is 
The velocity of the particle toward the x-direction is 
The velocity of the particle toward the y-direction is
The velocity of the particle toward the z-direction is
Generally the force on this particle is mathematically represented as
So we have
substituting values
 + [(5.58*10^{4}) (0.700)]\r y)](https://tex.z-dn.net/?f=%5C%3D%20F%20%20%3D%20%287.7%20%2A10%5E%7B-8%7D%29%28%5B%20%28-2.61%2A10%5E%7B4%7D%29%20%280.700%29%5D%28-%5Cr%20%20z%29%20%2B%20%5B%285.58%2A10%5E%7B4%7D%29%20%280.700%29%5D%5Cr%20y%29)
So the z-component of the force is
Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).
Answer:
129 J/Kg°C
Explanation:
Given :
Mass of gold, m = 1.2kg
Quantity of heat applied, Q = 3096 J
Temperature, t2 = 40°C
Temperature, t1 = 20°C
Change in temperature, dt = (40-20)°C = 20°C
Using the relation :
Q = mcdt
Where, C = specific heat capacity of gold
3096 = 1.2kg * C * 20°C
3096 J = 24kg°C * C
C = 3096 J / 24 kg°C
C = 129 J/Kg°C
Answer:
v = 57.2 m/s
Explanation:
The average velocity of the train can be defined as the total distance covered by the train divided by the time taken by the train to cover that distance. Therefore, we will use the following formula to find the average velocity of the train:
v = s/t
where,
s = distance covered = 460 km = (460 km)(1000 m/1 km) = 4.6 x 10⁵ m
t = time taken to cover the distance = 2 h 14 min
Now, we convert it into minutes:
t = (2 h)(60 min/1 h) + 14 min
t = 120 min + 14 min = (134 min)(60 s/1 min)
t = 8040 s
Therefore, the value of velocity will be:
v = (4.6 x 10⁵ m)/8040 s
<u>v = 57.2 m/s</u>
By using ramps you can easily push or pull the object up the ramp.
