Answer:
Explanation:
The capacitance of the electrode is given by:
where
C is the capacitance
Q is the charge on the electrode
V is the potential difference
In this problem, we have
V = 9.0 V
Substituting into the equation, we find
(5 nF)
Question 9: All parts thank you !
1 answer:
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Answer:
Explanation:
The first image that I attached to this solution is the diagram of a truth table for an 8 to 3 bit encoder.
The second image gives a sketch of the schematic.
The Boolean expression for the priority encoder including its zero inputs is defined in the third image attached.
Below is a snippet of the code for an 8 to 3 bit Priority encoder:
library IEEE;
use IEEE.STD_LOGIC_1164.all;
entity encoder8_3 is
port(
din : in STD_LOGIC_VECTOR(7 downto 0);
dout : out STD_LOGIC_VECTOR(2 downto 0)
);
end encoder8_3;
architecture encoder8_3_arc of encoder8_3 is
begin
dout <= "000" when (din="10000000") else
"001" when (din="01000000") else
"010" when (din="00100000") else
"011" when (din="00010000") else
"100" when (din="00001000") else
"101" when (din="00000100") else
"110" when (din="00000010") else
"111";
end encoder8_3_arc;
