Answer:
5 moles of O2are required, you can see it in your equation.
Answer:
2 seconds
Explanation:
v = at + v₀
19.62 m/s = (9.81 m/s²) t + 0 m/s
t = 2 s
Answer:
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
Explanation:
Given that
Yield strength ,Sy= 240 MPa
Tensile strength = 310 MPa
Elastic modulus ,E= 110 GPa
L=380 mm
ΔL = 1.9 mm
Lets find strain:
Case 1 :
Strain due to elongation (testing)
ε = ΔL/L
ε = 1.9/380
ε = 0.005
Case 2 :
Strain due to yielding


ε '=0.0021
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
For computation of load strain due to testing should be less than the strain due to yielding.
Answer:
Use the form of equation:
Q=mL
You have the specific latent heat of vaporization L = 2.260*10^{6}
And Q, the heat energy supplied, which equals 1695 KJ = 1695*10^{3} J
So you can get the mass by substitution in the formula below.