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Tcecarenko [31]

3 years ago

8

A common prism or grating shows the solar spectrum to be a rainbow of colors. But if you spread the spectrum out enough you begi

n to see other things. What are they?

1 answer:

mafiozo [28]3 years ago

6 0

I think it's spectrum wavelengths

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What is the formula to calculate the GPE of an object?

Bas_tet [7]

Answer:

mass x gravity x height

Explanation:

Gravitational potential energy is measured in jules

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What is the difference between current electricity and static electricity

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The most significant difference between the static and current electricity is that in static electricity the charges are at rest and they are accumulating on the surface of the insulator. Whereas in current electricity the electrons are moving inside the conductor.

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What is the importance of law of conservation of mass

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3 years ago

You push a box out of a carpeted room and along a hallway with a waxed linoleum floor. While pushing the crate 3 m out of the ro

mylen [45]

The total work done is equal to 134 J.

<h3>Work</h3>

The work formula is characterized as the multiplication of the force performed and the distance in which the movement was performed, so that:

$W = F \times d$

Thus, it is enough to calculate the value of the work in each movement and add to find the total work, so that:

$W_1 = 3 \times 28 = 84J\\W_2= 4 \times 14 = 56J\\W_3 = (-1.2) \times 5 = 6J$

$84 + 56 + (-6) = 134J$

So, the total work done is equal to 134 J.

Learn mor about work in: brainly.com/question/4095205

8 0

2 years ago

Sand falls from a conveyor belt at a rate of 30 m3m3/min onto the top of a conical pile. The height of the pile is always 3535 o

Reil [10]

Explanation:

As the given data is as follows.

h = $\frac{3}{5}d$

= $\frac{3}{5} \times (2r)$

Also, we know that r = $\frac{4}{3}h$

and Volume (V) = $\frac{1}{3} \pir^{2}h$

= $\frac{1}{3} \pi (\frac{4}{3}h)^{2} h$

= $\frac{16}{27} \pi h^{3}$

And, $\frac{dV}{dt} = \frac{3 \times 16}{27} \pi h^{2} \frac{dh}{dt}$

$\frac{dV}{dt} = \frac{16}{9} \pi h^{2} \frac{dh}{dt}$

Putting the given values into the above formula as follows.

$\frac{dV}{dt} = \frac{16}{9} \pi h^{2} \frac{dh}{dt}$

$30 m^{3}/min = \frac{16}{9} \pi (2)^{2} \frac{dh}{dt}$

[tex]\frac{dh}{dt} = 1.343 m/min

or, = 134.3 cm/min (as 1 m = 100 cm)

thus, we can conclude that the height changing at 134.3 cm/min when the pile is 2 m high.

4 0

3 years ago