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3 years ago

14

A photon with a frequency of 5.48 × 1014 hertz is emitted when an electron in a mercury atom falls to a lower energy level. Iden

tify the color of light associated with this photon.

1 answer:

ludmilkaskok [199]3 years ago

3 0

The color should be green.

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What is the weight of a truck that has a mass of 3500kg?

aleksley [76]

Answer:

7716.179 pounds? Are you asking for a conversion or something different?

7 0

3 years ago

The c-cl bond dissociation energy in cf3cl is 339 kj/mol. What is the maximum wavelength of photons that can rupture this bond?

ruslelena [56]

Answer:

3.53*10^{-7} m

Explanation:

Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

$1mol=6.022*10^{23}molecule$

Hence, we have

$E_d=339\frac{10^{3}J}{mol}*\frac{1mol}{6-022*10^{23}molecules}=5.62*10^{-19}J/molecule$

but the energy is also:

$E_d=h\nu =\frac{hc}{\lambda}\\\\\lambda=\frac{hc}{E_d}$

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

$\lambda=\frac{(6.62*10^{-34}Js)(3*10^{8}m/s)}{5.62*10^{-19}J}=3.53*10^{-7}m$

hope this helps!

7 0

3 years ago

Read 2 more answers

Anyone knows what this is?

shepuryov [24]

I think it is D.) “Cycles around” but I am not positive.

5 0

3 years ago

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

Lyrx [107]

Answer:

$\theta=4.64^{\circ}$

Explanation:

It is given that,

The frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

Slit separation, $d=2.2\times 10^{-5}\ m$

Let $\theta$ is the angle away from the central bright spot the third bright fringe past the central bright spot occur. The condition for bright fringe is :

$d\ sin\theta=n\lambda$

n = 3

$\lambda=\dfrac{c}{f}$

$d\ sin\theta=\dfrac{nc}{f}$

$sin\theta=\dfrac{nc}{fd}$

$sin\theta=\dfrac{3\times 3\times 10^8}{5\times 10^{14}\times 2.2\times 10^{-5}}$

$\theta=4.64^{\circ}$

So, at 4.64 degrees the third bright fringe past the central bright spot occur. Hence, this is the required solution.

3 0

3 years ago

If the Spirit of Australia, a boat,reaches speeds of 318.67 mph for 0.75 hours (45 minutes), what is the distance it traveled?

Rudiy27

Answer: 239.0025 miles.

Explanation:

First we have the relationship:

Distance = speed*time.

Because how it is worded, i guess that the boat can mantain a constant speed of 318.67 mph for 0.75 hours.

Then, we have the speed and the time, with those values we can find the distance.

speed = 318.67 mph

Time = 0.75 hours.

Distance = 318.67 mph*0.75h = 239.0025 miles.

6 0

3 years ago