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erik [133]
3 years ago
8

5. Explain the relationship between the relative sizeof an ion to its neutral atom and the

Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

The Relative Size of Atoms and Their Ions

In fact, the negative ion can be more than twice as large as the neutral atom. The only difference between an atom and its ions is the number of electrons that surround the nucleus. Example: A neutral chlorine atom contains 17 electrons, while a Cl- ion contains 18 electrons.

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Please help!!!!!!!!!!!!!!!
svlad2 [7]
The 2nd one is the right answer

Hope this helped
3 0
3 years ago
1. How will you differentiate physical from chemical change in terms of the
Tpy6a [65]

Answer:

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.

3 0
3 years ago
How does an indicator differentiate between an acid and base?
Svet_ta [14]

Answer:

that is all I know sorry hope that may help you :)

Explanation:

Indicator is a substance which shows different colors in acidic and basic medium. Indicators can be natural (derived from natural sources) or artificial ( man-made) for example :

*Litmus is an indicator. Acid turns blue litmus into red while base turns red litmus into blue

* Turmeric solution does not show change in color (remains yellow) in acidic solution and turns red in basic solution.

8 0
2 years ago
Heelp
Alchen [17]
Balanced:
1. <span>Na2O + H2O ---> 2NaOH
2. </span><span>K2O + H2O ---> 2KOH
3. </span><span>MgO + H2O ---> Mg(OH)2
4. </span><span>CaO + H2O ---> Ca(OH)2
5. </span><span>SO2 + H2O ⇄ H2SO3
6. </span>SO3 + H2O ---> H2SO4
All except by 2 were balanced.
7 0
3 years ago
Please help ASAP
marta [7]

Answer:

0.1

Explanation:

We must first put down the equation of the reaction in order to guide our solution of the question.

2HNO3(aq) + Sr(OH)2(aq) -------> Sr(NO3)2(aq) + 2H2O(l)

Now from the question, the following were given;

Concentration of acid CA= ??????

Concentration of base CB= 0.299M

Volume of acid VA= 17.8ml

Volume of base VB= 24.7ml

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CA= CBVBNA/VANB

SUBSTITUTING VALUES;

CA= 0.299 × 24.7 ×2 / 17.8×1

CA= 0.8298 M

But;

pH= -log[H^+]

[H^+] = 0.8298 M

pH= -log[0.8298 M]

pH= 0.1

5 0
4 years ago
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