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Karo-lina-s [1.5K]
3 years ago
5

To navigate, a porpoise emits a sound wave that has a wavelength of 2.2 cm. The speed at which the wave travels in seawater is 1

522 m/s. Find the period of the wave.
Physics
1 answer:
Alenkasestr [34]3 years ago
3 0

To solve this problem we will apply the concept related to frequency, by which it is defined as the relationship between the speed of the wave and the wavelength. Since the frequency is the inverse of the period, this relationship will also be reversed. That is to say,

f = \frac{v}{\lambda}

Here,

v = Velocity

\lambda = Wavelength

Now the period is defined as,

T = \frac{1}{f}

Therefore

T = \frac{\lambda}{v}

Replacing we have that,

T = \frac{2.2*10^{-2}}{1522}

T = 1.445*10^{-5}s

Therefore the period of the wave is 1.445*10^{-5}s

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Plz plz help ...i really need steps for this answer
bija089 [108]

Answer:

3.9 seconds

Explanation:

Use constant acceleration equation:

y = y₀ + v₀ t + ½ at²

where y is the final position,

y₀ is the initial position,

v₀ is the initial velocity,

a is the acceleration,

and t is time.

Given:

y = 0 m

y₀ = 15 m

v₀ = 15 m/s

a = -9.8 m/s²

Substituting values:

0 = 15 + 15t + ½ (-9.8) t²

0 = 15 + 15t − 4.9t²

0 = 4.9t² − 15t − 15

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 15 ± √((-15)² − 4(4.9)(-15)) ] / 2(4.9)

t = [ 15 ± √(225 + 294) ] / 9.8

t = (15 ± √519) / 9.8

t = -0.79 or 3.9

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