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masha68 [24]
3 years ago
12

A 0.22-caliber handgun fires a 29-g bullet at a velocity of 770. m/s. calculate the de broglie wavelength of the bullet.

Physics
1 answer:
True [87]3 years ago
3 0

solution:

\lambda =\frac{h}{mv}\\
h is planck's constant=6.626\times10^-34j.sec\\
m=mass=29g\\
=28\times10^-3kg\\
v=770m/sec\\
\lambda=\frac{6.626\times10^-34j.sec}{29\times10^-3\times770}\\

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