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tensa zangetsu [6.8K]
3 years ago
7

Determine la densidad de un cuerpo cuyo volumen es 354 cm3 y su masa 185 g.

Physics
1 answer:
Likurg_2 [28]3 years ago
5 0

Answer:

ni idea we. yo también necesitoe SA respuesta

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A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement
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Answer:

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity, u_y= u\ sin \theta = 60sin(60^0)

The magnitude of the displacement after 5s is calculated as;

h = u_yt -\frac{1}{2} gt^2\\\\h = 60sin (60^0)\times 5 - \frac{1}{2} (9.8)(5)^2\\\\h = 259.81-122.5\\\\h = 137.31 \ m

Therefore, the magnitude of the displacement after 5s is 137.31 m.

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