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dmitriy555 [2]
3 years ago
12

The table shows the values of a function f(x). What is the average rate of change of f(x) from 1 to 4?

Mathematics
2 answers:
Sav [38]3 years ago
6 0

Answer:

-80

Step-by-step explanation:

The average rate of change is

a.r.c = f(4) - f(1)

        --------------

             4-1

f(4) = 244 and f(1) = 484

a.r.c = 244  - 484

        --------------

             3

        = -240/3

      =-80

eduard3 years ago
4 0

Answer:

The average rate of change of f(x) from 1 to 4 is -80.

Step-by-step explanation:

The average rate of change of f(x) from a to b is defined as

m=\frac{f(b)-f(a)}{b-a}

The average rate of change of f(x) from 1 to 4 is defined as

m=\frac{f(4)-f(1)}{4-1}

m=\frac{f(4)-f(1)}{3}

From the given table it is clear that the the value of the function is 244 at x=4 and 484 at x=1. So f(4)=244 and f(1)=484. Put these values in the above equation.

m=\frac{244-484}{3}

m=\frac{-240}{3}

m=-80

Therefore the average rate of change of f(x) from 1 to 4 is -80.

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So, to get the rate he grew in those months we have:

\frac{\frac{13}{3} \text{inches}}{\frac{7}{2}\text{months}} =\frac{26\text{inches}}{21\text{months}}

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Step-by-step explanation:

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3 years ago
What is the value of y
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Trucks that travel on highways have to stop at various locations to be weighed and inspected for safe brakes and light systems.
IrinaVladis [17]

Answer:

The reuired probability is 0.756

Step-by-step explanation:

Let the number of trucks be 'N'

1) Trucks on interstate highway N'= 76% of N =0.76N

2) Truck on intra-state highway N''= 24% of N = 0.24N

i) Number of trucks flagged on intrastate highway  = 3.4% of N'' = \frac{3.4}{100}\times 0.24N=0.00816N

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Part a)

The probability that the truck is an interstate truck and is not flagged for safety is P(E)=P_{1}\times (1-P_{2})

where

P_{1} is the probability that the truck chosen is on interstate

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5 0
3 years ago
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Salsk061 [2.6K]

Answer:

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(4,0)

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Step-by-step explanation:

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