Hello,
After decrypting the question:
f(x)=2x^4-4x^3-11x^2+3x-6
f(-2)=2(-2)^4-4(-2)^3-11(-2)^2+3*(-2)-6=2*16+32-44-6-6=8
(a). To calculate Y at equilibrium
Y = C + I + G
Y = 40 + 0.8(Y – 0 + 10 + 20)
Y = 350
(b). To calculate C, I and G at Equilibrium
C = 40 + 0.8 Y
Since Y = 350
C = 40 + 0.8(350)
C = 40 + 280
C = 320
I = 20
G = 10
(c).To find
equilibrium Y
Given,
EX = 4 + 3EP/P
IM = 8 + 0.1 (Y - T) - 2EP/P
E = 3
P = 1
P = 1.5
Y = 170
Set the height to h, and the width to w.
We know that wh=190 and h=2w-1.
Substituting 2w-1 for h, we have:
w(2w-1)=190
So:
2w^2-w-190=0
Factoring this equation, we get (2w+19)(w-10)=0. The solutions to this equation are -9.5 and 10, but clearly the width must be positive, Substituting 10 for the width, we get 10*2-1=19 for the height.
Answer:
it's a substitution because y was solved
Step-by-step explanation:
2x +2(3x-7)=10
you just replace the "y' by the solved y
then you solve parenthesis and continue the rest.