Step-by-step explanation:
You have to do first and second derivatives :
y = a sin 3x + b cos 3x
dy/dx = 3a cos 3x - 3b sin 3x
d²y/dx² = - 9a sin 3x - 9b cos 3x
Next, you have to compare it :
let d²y/dx² = ky,
-9a sin 3x - 9b cos 3x = k(a sin 3x + b cos 3x)
-9(a sin 3x + b cos 3x) = k(a sin 3x + b cos 3x)
Therefore, k is equals to 9.
I agree with you because theta could be acute or obtuse, and if obtuse, negative value.
Answer:
d = 90°
e = 41°
f = 139°
Step-by-step explanation:
d + 90° = 180° (Angles in linear pair)
-> d = 180° - 90°
-> d = 90°
e = 41° (vertical angles)
f + 41° = 180° (Angles in linear pair)
-> f = 180° - 41°
-> f = 139°
<span>10<span>(<span><span>122<span>(13)</span></span><span>(12)</span></span>)</span></span><span>=<span><span>10<span>(122)</span></span><span>(156)</span></span></span><span>=<span><span>(10)</span><span>(19032)</span></span></span><span>=<span>190320
Hope You understand
This is just basic multiplication.</span></span>
I hope this helps you
y+4/3=x^5
x= (y+4/3)^1/5
f^-1(x)=(x+4/3)^1/5