Answer:
B. Precipitation
Explanation:
Precipitation is the scientific term for rain
m(O2)=50g
m(H2)=50g
m(H2O)-?
n2(H2)-?
2H2 + O2 = 2H2O
n(O2)= m (O2)/M(O2) =50g / 32 g/mol= 1,56 mol.
n(H2)= m (H2)/M(H2) =50g / 2 g/mol= 25 mol.
Since oxygen gas is the limiting reactant,
n(O2)< 2 n(H2) from reaction.
n(H2O)= 2n(O2)= 2n (H2 reac.)=2*1,56 mol=3,12mol.
m(H2O)=n(H2O)*M(H2O)= 3,12mol* 18 g/mol.
n2(H2)= n(H2) - n (H2 reac.)=25mol - 3,12mol=21,88mol.
Answer:
Option E
RbCL<CH3OH< CH3Cl< CH4
Explanation:
The boiling temperature of an organic compound increases with the increase in number of carbon atoms and hence as the length of the hydrocarbon chain increases the boiling temperature also increase due to increase in force of attraction between the molecules. Also presence of strong molecules such as OH – COOH also increases the boiling temperature while Cl and other elements with high electronegativity reduces the boiling temperature
Hence, the correct order of increasing boiling temperature is option E
RbCL<CH3OH< CH3Cl< CH4
Answer:
a. 2,3-dimethylbutane < 2-methylpentane < n-hexane
Explanation:
The boiling point of alkanes is highly affected by the degree of branching in the molecule. Branched alkanes generally have a lower boiling point than unbranched alkanes.
The reason for the higher boiling point of unbranched alkanes is because they have greater vanderwaals forces acting between their molecules due to their larger surface area. Recall that branched alkanes have a lesser surface area compared to unbranched alkanes.
n-hexane is an unbranched alkane hence it will have the highest boiling point followed by 2-methyl pentane and lastly 2,3-dimethyl butane. The boiling point continues to decrease as the extent of branching increases.