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tatuchka [14]
3 years ago
6

Consider the formula for glucose: C6H12O6. What does this indicate about the relationship of the reactants to glucose?A. Twelve

water (H2O) molecules were used to make it. B. Twelve hydrogen (H2) molecules were used to make it. C. Six oxygen (O2) molecules were used to make it. D. Six carbon dioxide (CO2) molecules were used to make it.
Chemistry
2 answers:
VLD [36.1K]3 years ago
7 0
<span>I think the correct answer from the choices presented above is option D. The chemical reaction for the formation of glucose is:

6CO2+6H2O=C6H12O6+6O2.

From the balanced chemical reaction, six carbon dioxide molecules were used to make glucose.

Hope this answers the question.</span>
Arisa [49]3 years ago
4 0

The correct answer is:

D.Six carbon dioxide (CO2) molecules were used to make it.

The explanation:

when The balanced equation for the reaction of formation of glucose is:

6CO2+6H2O=C6H12O6+6O2.

From the balanced chemical reaction:

1- six carbon dioxide molecules were used to make glucose.

2- six water (H2O) molecules were used to make glucose.

3- six oxygen (O2) molecules were produced

So the correct answer is D Six carbon dioxide (CO2) molecules were used to make it because O2 is a product not reactant, and there is only 6 H2O molecules not 12.

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What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1? 6.4 × 10−4 g 6.4 × 10−3 g
eduard

Compete Question:

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1?

               Passage: "16 mmol of CDP in 1 L of buffer"

                                       

Answer:

6.4 × 10-2 g  

Explanation:

  Mass = Mole × Molar Mass

   we are given from the question that 16 mmol of CDP is in 1 L of buffer

    this mean that we have 16 × 10^-3 moles of CDP in 1 liter of buffer.

so the mass of CDP in one liter of buffer will be calculate as,

         mass of CDP = 16 × 10^-3 × 403g mol−1

                               = 64 × 10^-1

                               = 6.4 g/L

But because the question

asks us about the mass of CDP in 10 mL of solution, we will go further to calculate it like this:

6.4 g/L × 10 mL

6.4 g/L × 0.01 L  = 6.4 × 10^-2

8 0
4 years ago
Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym
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Answer:

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Given that:

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You dissolve 3 moles of NaCl into 12 L of water. What is the Molarity?​
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