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Masteriza [31]
3 years ago
11

. A normal population has a mean of 80.0 and a standard deviation of 14.0. a. Compute the probability of a value between 75.0 an

d 90.0. b. Compute the probability of a value of 75.0 or less. c. Compute the probability of a value between 55.0 and 70.0. 19. Suppose the Internal Revenue Service reported that the mean
Mathematics
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:

a. 0.40198

b. 0.36049

c. 0.20046

Step-by-step explanation:

To solve for this we make use of the z score formula.

z-score formula is

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

a. Compute the probability of a value between 75.0 and 90.0.

For x = 75

From the question, we know that

mean of 80.0 and a standard deviation of 14.0.

z = (x - μ)/σ

z = 75 - 80/ 14

z = -0.35714

Using the z score table to find the probability

P-value from Z-Table:

P(x = 75) = P(z = -0.35714)

= 0.36049

For x = 90

z = 90 - 80/14

z = 0.71429

Using the z score table to find the probability

P-value from Z-Table:

P(x = 90) = P(z = 0.71429)

= 0.76247

The probability of a value between 75.0 and 90.0 is:

75 < x < 90

= P( x = 90) - P(x = 75)

= 0.76247 - 0.36049

= 0.40198

Therefore, probability of a value between 75.0 and 90.0 is 0.40198

b. Compute the probability of a value of 75.0 or less.

For x = 75

From the question, we know that

mean of 80.0 and a standard deviation of 14.0.

z = (x - μ)/σ

z = 75 - 80/ 14

z = -0.35714

Using the z score table to find the probability

P-value from Z-Table:

P(x ≤ 75) = 0.36049

c. Compute the probability of a value between 55.0 and 70.0.

For x = 55

From the question, we know that

mean of 80.0 and a standard deviation of 14.0.

z = (x - μ)/σ

z = 55 - 80/ 14

z = -1.78571

Using the z score table to find the probability

P-value from Z-Table:

P(x = 55) = P(z = -1.78571)

= 0.037073

For x = 70

z = 70 - 80/14

z = -0.71429

Using the z score table to find the probability

P-value from Z-Table:

P(x = 70) = P(z = -0.71429)

= 0.23753

The probability of a value between 55.0 and 70.0 is:

55 < x < 70

= P( x = 70) - P(x = 55)

= 0.23753 - 0.037073

= 0.200457

Approximately to 4 decimal place = 0.20046

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