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Svetach [21]
3 years ago
5

Am i correct so far on the first question? And how do i convert to molecules... I use avogadro's number, right?

Chemistry
1 answer:
Talja [164]3 years ago
4 0
I'm pretty sure that you multiply the number of moles by avogadro's number (6.02x10^23)... you may want to check.
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What are examples of chemical change
VladimirAG [237]

Answer:

Almost everything in our surroundings represent chemical change

Explanation:

●Rusting of iron in presence of moisture and oxygen.

●Burning of wood.

●Milk becoming curd.

●Formation of caramel from sugar by heating.

●Baking of cookies and cakes.

●Cooking any food.

●Acid-base reaction.

●Digestion of food.

3 0
3 years ago
A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.
BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\  &=185.59\text{ g/mol} \end{aligned}

Dimensional Analysis:

\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

8 0
3 years ago
Who knows how to do this please help
Fofino [41]

Answer: You forgot to zero the balance

Explanation:

5 0
3 years ago
The hindbrain includes the:
densk [106]
The answer is B mark me as Brainliest while your at it
4 0
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3 the h2o molecule itself is small in size
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