Gay-Lussac's law states the relationship between pressure of gas with temperature. It states that pressure of gas is directly proportional to temperature of gas at constant volume.
P/T = k
where P - pressure, T-temperature and k-constant
P1/T1 = P2/T2
where parameters for the 1st instance are on the left side and parameters for the 2nd instance are on the right side.
2500 atm/ 290 K = P/320 K
P = 2759 atm
Answer:
by the VSEPR theory.
Explanation:
This question is asking for the bond angle of the 
bond in 
. The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?
Note that "electron domains" refer to covalent bonds and lone pairs collectively.
- Each nonbonding pair (lone pair) of valence electrons counts as one electron domain.
- Each covalent bond (single bond, double bond, or triple bond) counts as exactly one electron domain.
For example, in , the carbon atom at the center of that bond has two electron domains:
- This carbon atom has two double bonds: one
bond and one 
bond. Even though these are both double bonds, in VSEPR theory, each of them count only as one electron domain. - Keep in mind that there are only four valence electrons in each carbon atom. It can be shown that all four valence electrons of this carbon atom are involved in bonding (two in each of the two double bonds.) Hence, there would be no nonbonding pair around this atom.
In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this bond as three spheres on a stick. The central 
atom would be between the other atom and the 
atom.)
This linear geometry corresponds to a bond angle of .
The molarity of a solution is 0.909 M.
m(CaCl₂) = 82 g; mass of calcium chloride
M(CaCl₂) = 111 g/mol; molar mass of calcium chloride
n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)
n(CaCl₂) = 82 g ÷ 111 g/mol
n(CaCl₂) = 0.74 mol; amount of calcium chloride
V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride
c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)
c(CaCl₂) = 0.74 mol ÷ 0.812 L
c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride
Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.
More about molarity: brainly.com/question/26873446
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which experiment please involve a clip
C the answer is cesium, study's show that it has the lowest ionization out of all elements. Hope this helped!
