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Pachacha [2.7K]
3 years ago
9

What is formed when two or more different elements chemically combine?

Chemistry
1 answer:
Marat540 [252]3 years ago
3 0
B.compound Because compound is when two element are combined or joined chemically
You might be interested in
What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? A: 2.95 K
harina [27]

Option D: 246 K

According to ideal gas law:

PV=nRT ...... (1)

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature of the gas. The value of R is 0.082 atm L K^{-1}mol^{-1}.

Number of moles of gas are 0.750 mol, volume of cylinder is 6850 mL and pressure of gas is 2.21 atm.

First converting volume from mL to L

1 mL=10^{-3}L

Thus,

6850 mL=6.850 L

Putting the values in equation (1),

(2.21 atm)(6.850 L)=(0.750 mol)(0.082 atm L K^{-1}mol^{-1}T

Rearranging

T=\frac{(2.21 atm)(6.850 L)}{(0.750 mol)(0.082 atm L K^{-1}mol^{-1})}=246 K,

Therefore, temperature of the gas is 246 K.


8 0
3 years ago
Read 2 more answers
Given the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4
MAXImum [283]

<u>Answer:</u>

(a): The expression of equilibrium constant is K_{eq}=\frac{[NO]^2}{[N_2][O_2]}

(b): The equation to solve the concentration of NO is [NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}

(c): The concentration of NO is 0.0017 M.

<u>Explanation:</u>

The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term K_{eq}

(a):

The given chemical equation follows:

N_2+O_2\rightarrow 2NO

The expression for equilbrium constant will be:

K_{eq}=\frac{[NO]^2}{[N_2][O_2]}

(b):

The equation to solve the concentration of NO follows:

[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}            ......(1)

(c):

Given values:

K_{eq}=1.2\times 10^{-4}

[N_2]_{eq}=0.166M

[O_2]_{eq}=0.145M

Plugging values in equation 1, we get:

[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}

[NO]=\sqrt{2.88\times 10^{-6}}

[NO]=0.0017 M

Hence, the concentration of NO is 0.0017 M.

3 0
3 years ago
What change would increase the amount of solid solute able to be dissolved in liquid water?
Agata [3.3K]

Answer:

D: Increasing temperature

Explanation:

From collision theory, we know that the more the increase in collisions, the faster the rate of the chemical reaction.

Now, the amount of solid solute in a solvent will change with a corresponding change in temperature. What we mean is that, the higher the temperature increases, the higher the number of collisions between the solvent molecules as well as leading to an increase in the solute particles which will mean an increase in the amount of the solid solute dissolved. The correct answer is option D.

4 0
3 years ago
(A) H2SeO4(aq) + 2 Cl-(aq) + 2 H+(aq) → H2SeO3(aq) + Cl2(g) + H2O(l) (B) S8(s) + 8 O2(g) → 8 SO2(g) (C) 3 Br2(aq) + 6 OH-(aq) →
AVprozaik [17]

Answer:

C)

Explanation:

Oxidation occurs when the Nox number increases and a reduction occurs when the Nox number decreases. So, let's verify in which reaction the same reactant has elements that both occur after the reaction.

A) H₂SeO₄: H = +1, O = -2 (fixed)

Se: x +2*1 + 4*(-2) = 0

x + 2 - 8= 0

x = +6

Cl⁻: -1 (ions have Nox equal to its charge)

H⁺: +1

H₂SeO₃: H = + 1, O = -2

Se: x +2*1 + 3*(-2) = 0

x + 2 -6 = 0

x = + 4 (Se reduces)

Cl₂: Cl = 0 (simple molecule, so Cl oxides)

H₂O: H = +1, O = -2

B) S₈: S = 0

O₂: O = 0

SO₂: O = -2, S: x + 2*(-2) = 0 -> x = +4 (S oxides and O reduces)

C) Br₂: Br = 0

OH⁻ : O = -2, H = +1

Br⁻ = -1 (Br reduces)

BrO₃⁻: O = -2, Br: x +3x(-2) = -1 -> x = +5 (Br oxides)

H₂O: H = +1, O = -2

D) Ca²⁺: Ca = +2

SO₄²⁻: O = -2, S: x +4*(-2) = -2 -> x = +6

CaSO₄: O = -2, S = +6, Ca = +2

E) PtCl₄: Cl = -1 (fixed), Pt: x + 4*(-1) = 0 -> x = +4

Cl⁻: Cl = -1

PtCl₆²⁻: Cl = -1, Pt = x + 6*(-1) = -2 -> x = +4

So, only in letter C Br₂ is undergoes both oxidation and reduction.

4 0
3 years ago
Mrs. DeFord wanted to know whether or not her students would do better on a quiz if she promised them candy.
marta [7]

Answer:

a.) Independent Variable: # of candy bars promised to each group

[ The Independent Varaiable is what you change in the experiment]

b.) Dependent Variable: Quiz Scores

[ The Dependent Variable is what you're testing in the experiment; what the experiment should affect]

c.) Constant(s): Same Quiz, same number of gender kids in each group, same age kids in each group, same ability, and same background. [and same time, I'm assuming.]

[Constants are what you keep the same in the experiment; what you're not changing.]

d.) Testable Question: Will promising kids candy make them do better on tests and quizzes? [or something along this lines of this]

[The Testable Question is what you're trying to find out in the experiment]

e.) Hypothesis: The more candy the students were promised, the better results Mrs. DeFord would get from them.

[The Hypothesis is what the person performing the experiment expects will happen; an educated guess]

f. Formal Conclusion: Data shows that kids who were promised more candy had a better average than kids who were promised less candy/none. Mrs. DeFord's hypothesis was correct, since she assumed the more candy the students were promised, the better they would do on the quiz.

[The Formal Conclusion is what you have learned from the experiment, and wether or not the hypothesis was correct or not.]

I hope this helps! :)

6 0
4 years ago
Read 2 more answers
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