Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
Answer:
y/2 = tan(60) => y = 2 tan(60) = 2sqrt(3) = 3.464
Step-by-step explanation:
I think the answer that u r looking for is C
The applicable formula is;
A = P(1+r)^nt
Where
A = Accumulate amount
P = Initial invested amount
r = Annual interest rate
n = Number of payments in a year
t = Time in years
First part of the question: Accumulated amount after 18 years
Substituting;
A = 1000(1+0.01)^12*18 = $8,578.61
Since the car costs $15,000 and the amount in the bank after 18 years is $8,578.61, Anthony wouldn't be able to afford the car.
Second part of the question: The amount which should have been deposited for Antony to afford the car after 18 years
15,000 = P (1+0.01)^12*18
15,000 = P*8.5786
P = 15,000/8.5786 = $1,748.54
Therefore, for Antony to afford the $15,000 after 18 years, the mum should have deposited $1,748.54.
