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slavikrds [6]
3 years ago
9

Please please help me

Mathematics
1 answer:
Yanka [14]3 years ago
6 0
Let A, M, and w represent Angelo's distance per week, Marc's distance per week, and the number of weeks of this regimen, respectively.
.. A = w +7 . . . . . . . Angelo's distance goes up 1 mile/week each week
.. M = 2w +4 . . . . . Marc's distance goes up 2 miles/week each week

a) A = M
.. w +7 = 2w +4
.. 3 = w . . . . . . . . . . subtract w+4

After 3 weeks Angelo and Marc will be running the same distance.


b) A = M = 3+7 = 2*3+4 = 10

That distance will be 10 miles per week.

_____
This problem can be a little confusing because "miles per week" is a rate, and we're talking about the rate of increase of that rate: 1 or 2 miles per week per week. It might be easier to think of the numbers as "weekly distance", rather than "miles per week".
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Add the sum and difference identities for sin x to derive 1/2 [sin(x+y)+sin(x-y)]=sin x cos y
Solnce55 [7]

Answer:

true

Step-by-step explanation:

1/2 (sin(x+y)+sin(x-y))

= 1/2 (sin x cos Y + cos x sin y + sin x cos y - cos x sin y)

= 1/2 * 2 sin x cos y

= sin x cos y

The expression is true.

3 0
3 years ago
A sample of 10 adult elephants had an average weight of 12,556 pounds. The standard deviation
kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.25

The margin of error is:

M = T*s = 3.25*25 = 81

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

6 0
3 years ago
1000^m/100^n=10^zexpress z in terms of m and n
Hitman42 [59]

\dfrac{1000^m}{100^n}=10^z\\\\\dfrac{10^{3m}}{10^{2n}}=10^z\\\\10^{3m-2n}=10^z\\\\\boxed{z=3m-2n}

3 0
3 years ago
Let f(x) = 6x2 + 5 and g(x) = 3x-5. Find g(f(0))
devlian [24]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
Name the three different types of proofs you saw in this lesson. Give a description of each.
natka813 [3]

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we need to see a picture of something to answer your question.

4 0
3 years ago
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