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slavikrds [6]
3 years ago
9

Please please help me

Mathematics
1 answer:
Yanka [14]3 years ago
6 0
Let A, M, and w represent Angelo's distance per week, Marc's distance per week, and the number of weeks of this regimen, respectively.
.. A = w +7 . . . . . . . Angelo's distance goes up 1 mile/week each week
.. M = 2w +4 . . . . . Marc's distance goes up 2 miles/week each week

a) A = M
.. w +7 = 2w +4
.. 3 = w . . . . . . . . . . subtract w+4

After 3 weeks Angelo and Marc will be running the same distance.


b) A = M = 3+7 = 2*3+4 = 10

That distance will be 10 miles per week.

_____
This problem can be a little confusing because "miles per week" is a rate, and we're talking about the rate of increase of that rate: 1 or 2 miles per week per week. It might be easier to think of the numbers as "weekly distance", rather than "miles per week".
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The temperature in Anchorage, Alaska at 6:00 am was 2°C. If the temperature drops 2 degrees each hour, what is the temperature i
Fittoniya [83]

Answer:

-12°C

Step-by-step explanation:

6AM = 2°C

8AM= -2°C

10AM= -6°C

12AM= -8°C

2PM= -12°C

5 0
3 years ago
Point D is the in center of triangle ABC. Write an expression for the length x in terms of the three side lengths AB,
KiRa [710]

Answer:

x =  \frac{2(A_T) }{(AB)  +  (AC) + (BC)}

6 0
2 years ago
two observers, Anna and Bryan. sight a kite at angles 44 degrees and 66 degrees. respictively. if anna is located 20m from the k
Arada [10]

Answer:

28.6m

Step-by-step explanation:

this question is very incomplete. it requires a number of assumptions to give an answer. the main one - where is Bryan located relative to Anna ? I assume diametrically on the opposite side of the kite. because he has the steeper angle, it is clear that he is nearer to the kite.

so, I guess, we have to add his distance to the kite to her distance to the kite to get the distance between her and him.

but he could be on any point on a circle around the kite to have the same viewing angle, and we would have no clue about where on that circle.

as the other extreme alternative, he could be on the same line to the kite as Anna. and then we would have to subtract his distance from her distance.

but again, we assume he is exactly on the other side of the kite.

anyway, each person creates a right-angled triangle with the kite:

there is the direct line of sight as the base line or Hypotenuse (c).

there is the line on the ground from the person to the point on the ground directly under the kite as one side.

there is the line representing the height of the kite above ground as the other side. we let this start at the height of the eyes of the watching person.

and we assume that both persons are of the same height (so the height of the kite relative to their eyes is the same for both).

let's start with Anna.

the side a of Anna's triangle is

a = 20m

angle between a and c = 44 degrees

we know the angle between a and b is 90 degrees.

therefore the angle between b and c = 180-90-44 = 46 degrees.

now we use the law of sines :

a/sin(bc) = b/sin(ac) = c/sin(ab)

we know sin(ab) = sin(90) = 1

20/sin(46) = b/sin(44)

b = 20×sin(44)/sin(46) = 19.31... m = height of the kite

now to Bryan.

now we know his b (height of the kite) = 19.32... m

his angle between a and c is 66 degrees.

his angle between a and b is also 90 degrees.

therefore his angle between b and c = 180-90-66 = 24 degrees.

19.31/sin(66) = a/sin(24)

a = 19.31×sin(24)/sin(66) = 8.6 m

based on our assumption that they are standing opposite from each other in relation to the kite their distance is

20 + 8.6 = 28.6m

3 0
3 years ago
Find the slope of a parallel line to each given line y=-1/3x-4
Mumz [18]
Slope of parallel line to this would be -1/3x
4 0
2 years ago
Read 2 more answers
I dont quite understand this.. Check the picture and help
wariber [46]

5) 74.925

6) 470

i think this is correct but i'm not completely sure

6 0
3 years ago
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