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belka [17]
3 years ago
13

An alloy of bronze is manufactured by melting 51.2 g of copper with 6.84 g of tin. What is the percent copper in the bronze?

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

Percentage of copper = 88%

Explanation:

Given data:

Mass of copper = 51.2 g

Mass of tin = 6.84 g

Percentage of copper = ?

Solution:

Formula:

Percentage of copper = mass of copper / total mass × 100

Now we will determine the total mass:

Total mass = mass of copper + mass of  tin

Total mass = 51.2 g + 6.84 g

Total mass = 58.04 g

Now we will calculate the percentage of copper.

Percentage of copper = 51.2 g / 58.04 g × 100

Percentage of copper = 0.88 × 100

Percentage of copper = 88%

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Answer:

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Increase in temperature - more collisions every second with enough energy to break bonds

Explanation:

According to the collision theory, chemical reaction occurs as a result of collision between reacting particles. Only particles that possess energy above the activation energy of the reaction can collide and result in product formation. Collision of particles having energy less than the activation energy merely result in elastic collisions.

Adding a catalyst lowers the activation energy of the reaction. If the activation energy is lowered, more reactants collide and more of those collisions now have enough energy to break bonds.

When the temperature is increased, the particles become more energetic hence more collisions with energy to break bonds occur.

Increase in pressure brings the reactant particles into close proximity hence more collisions occur.

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3 years ago
Lauren walks 100m in half a minute. What must her speed have been to travel this distance?
tester [92]

Answer:

10/3 m/s. v=d/t. so 100/30 = 10/3

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3 years ago
For the second-order reaction below, the rate constant of the reaction is 9.4 x 10^-3 M^-1 s^-1. How long (in sec) is required t
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Answer : The time taken by the reaction is 2.2\times 10^2s

Explanation :

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

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k = rate constant = 9.4\times 10^{-3}M^{-1}s^{-1}

t = time = ?

[A_t] = final concentration = 0.40 M

[A_o] = initial concentration = 2.16 M

Now put all the given values in the above expression, we get:

(9.4\times 10^{-3})\times t=\frac{1}{0.40}-\frac{1}{2.16}

t=216.706s\aprrox 2.2\times 10^2s

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Answer:

C: solvent

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The rule which is followed is "like dissolve like". Polar solvent always dissolve polar solute while non polar solvent dissolve non polar substances.

Let consider the example of water and sodium chloride.

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