Answer:
3.6*105g CH4
Explanation:
The detailed solution is shown on the image. From the detailed chemical reaction, we calculate the mass of methane required in the standard combustion reaction of methane and use it to estimate the mass required to produce the quantity of heat required in the question.
The earth's core makes up 16% of the earths volume, but 32% of the earths mass.
Answer:
C₅H₈NO₄Na
Explanation:
Step 1: Given data
- Percentage by mass of Na in MSG: 13.6%
- Percentage by mass of C in MSG: 35.5%
- Percentage by mass of H in MSG: 4.8%
- Percentage by mass of N in MSG: 8.3%
- Percentage by mass of O in MSG: 37.8%
Step 2: Divide each percentage by the atomic mass of the element
Na: 13.6/22.99 = 0.592
C: 35.5/12.01 = 2.96
H: 4.8/1.01 = 4.75
N: 8.3/14.00 = 0.592
O: 37.8/16.00 = 2.36
Step 3: Divide all the number by the smallest one, i.e. 0.592
Na: 0.592/0.592 = 1
C: 2.96/0.592 = 5
H: 4.75/0.592 ≈ 8
N: 0.592/0.592 = 1
O: 2.36/0.592 ≈ 4
The empirical formula of MSG is C₅H₈NO₄Na.
Answer:
Explanation:
The relation between equilibrium constant and Ecell is given below .
E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K
E⁰cell = 1.46 - 1.21 = .25 V
n = 2
Putting the values
.25 = (8.314 x 298 lnK) / (2 x 96485 )
lnK = 19.47
K = 2.85 x 10⁸
2 )
Change in free energy Δ G
Δ G ⁰ = nE⁰ F
n = 4
E⁰ = .4 + .83 = 1.23 V
Δ G ⁰= 4 x 1.23 x 96485
= 474706 J / mol
3 )
E⁰cell = (RT / nF ) lnK
n = 2
1.78 = 8.314 x 298 lnK / 2 x 96485
lnK = 138.638
K = 1.62 x 10⁶⁰
Molar Mass: 300.0510 g/mol