Answer:
The 
of a substrate will be "10 μM".
Explanation:
The given values are:
![[Substract] = 40 \ \mu M](https://tex.z-dn.net/?f=%5BSubstract%5D%20%3D%2040%20%5C%20%5Cmu%20M)
Reaction velocity, 
As we know,
⇒ ![Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}](https://tex.z-dn.net/?f=Vo%3D%5Cfrac%7BK_%7Bcat%7D%5BE_%7Bt%7D%5D%5BS%5D%7D%7BK_%7Bm%7D%2B%5BS%5D%7D)
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
On subtracting "40" from both sides, we get
⇒ 
⇒ 
Answer:
Photosynthesis
Explanation:
Carbon cycle involves the exchange of components between the hydrosphere, biosphere and atmosphere. During carbon cycle, materials such as gases, minerals which are necessary for life are interchange. For example, animals pass out faeces on the soil which is rich in urea. Urea decomposes to provide nitrogen into the soil through bioactive bacterials. The nitrogen is used up by plants to grow. During photosynthesis, plants uses carbon dioxide and water to produce glucose and release oxygen for animals to use. It's like a purification system where one waste product from one organism is used by the other to survive.
Equation of photosynthesis
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂.
Well if the change is reversible then it is a physical change, but if not then it is a chemical change.
Answer: Bacterial species where observed Typical number on cell Distribution on cell surface
Escherichia coli (common pili or Type 1 fimbriae) 100-200 uniform
Neisseria gonorrhoeae 100-200 uniform
Streptococcus pyogenes (fimbriae plus the M-protein) ? uniform
Pseudomonas aeruginosa 10-20 polar
Explanation:
Pili are structures that extend from the surface of some bacterial cells.
These are hollow, non-helical, filamentous appendages.
Hope it helps you
Answer:
8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days
Explanation:
The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.
We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.
Initial amount of Thorium-234 available as per the question is 150 grams
So now we start with 150 grams of Thorium-234
So after 120.5 days the amount of sample that remains is 8.625g
In simpler way , we can use the below formula to find the sample left
Where
is the initial sample amount
n = the number of half-lives that pass in a given period of time.
