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hjlf
3 years ago
6

2' A mixture containing 2.75 gof ammonium chloride (NH4cl) in 5.0 g of water was heated to dissolve the solid and then allowed t

o cool in air. At 6f"C, the first crystals appeared in solution. What is the solubility of ammonium chloride (in g of NH4CIper 100 gof water) at 61 'C
Chemistry
1 answer:
Trava [24]3 years ago
6 0

Answer:

55g NH₄Cl / 100g Water

Explanation:

Solubility of a substance define the amount of solute per solvent in a saturated solution. The solution can dissolve additional solute if heated.

In the problem, as the first crystal appears at 61°C the solubility in this temperature is the concentration of the solution, that is:

2,75g NH₄Cl / 5,0g water ₓ 100 = <em>55g NH₄Cl / 100g Water</em>

<em></em>

I hope it helps!

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Determine the pH of a 2.8 ×10−4 M solution<br> of Ca(OH)2.
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Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

<h3>pH = 10.75</h3>
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