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3 years ago

8

Carbon dioxide gas is produced by the reaction of oxygen gas and solid carbon . Write a balanced chemical equation for this reac

tion

1 answer:

grandymaker [24]3 years ago

5 0

I think it’s like this.

C+2O→CO2

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Consider the following system at equilibrium:A(aq)+B(aq) <---> 2C(aq)Classify each of the following actions by whether it

velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On addition of reactant at equilibrium shifts the equilibrium in forward direction.
On addition of product at equilibrium shifts the equilibrium in backward direction.
On removal of reactant at equilibrium shifts the equilibrium in backward direction.
On removal of product at equilibrium shifts the equilibrium in forward direction.

$A(aq)+B(aq)\rightleftharpoons 2C(aq)$

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling A and halving B, equilibrium constant of the reaction = K'

$K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}$

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

$K=\frac{[C]^2}{[A][B]}$

On doubling B and C, equilibrium constant of the reaction = K'

$K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}$

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

5 0

3 years ago

Use the choose reaction drop down menu to see other equations, and balance them. Check your answers and then write the balanced

d1i1m1o1n [39]

3 and then you do that yea

6 0

2 years ago

What is the role of gluons?

igor_vitrenko [27]

The role of the gluons is to bind together the quarks that make up protons and neutrons. That is option D.

<h3>What are gluons?</h3>

Gluons are those particles found within an atom that are responsible for binding protons and neutrons together inside the nucleus of an atom.

The gluons are capable of binding the protons and neutrons together by holding together the quarks that makes up protons and neutrons.

These gluons are known to carry a color-anticolor charge which makes up the 9 types of gluons which include:

red anti-red,

red anti-blue,

red anti-green,

blue anti-red,

blue anti-blue,

blue anti-green,

green anti-red,

green anti-blue, and

green anti-green.

An atom is the smallest indivisible part of an element that can take part in a chemical reaction.

The proton is the positive particle of an atom which is found within the nucleus.

The neutron is the particle that is found in the nucleus of an atom which doesn't have any charge.

Learn more about atom here:

brainly.com/question/1805828

#SPJ1

8 0

1 year ago

Using Charles’s law, V1/T1 =V2/T2 and the information below, solve the question. If a balloon takes up 625L at 273K, what will t

pogonyaev

Answer:

The new volume is 808L.

Explanation:

First, you need to set up your proportion, using Charles's law.

V1 V2

<u> </u> = <u> </u>

T1 T2

Then, substitute for the ones you already know.

625 L V2

<u> </u> = <u> </u>

273 K 353 K

Then, you need to cross multiply.

625 x 353 = 273 x V2

Then, solve for V2.

220625 = 273 x V2

220625 ÷ 273 = V2

808 = V2

The final volume is 808L.

4 0

3 years ago

A) The average molecular speed in a sample of Ar gas at a certain temperature is 391 m/s. The average molecular speed in a sampl

diamong [38]

<u>Answer:</u>

<u>For A:</u> The average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u> The rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

<u>Explanation:</u>

<u>For A:</u>

The average molecular speed of the gas is calculated by using the formula:

$V_{gas}=\sqrt{\frac{8RT}{\pi M}}$

OR

$V_{gas}\propto \sqrt{\frac{1}{M}}$

where, M is the molar mass of gas

Forming an equation for the two gases:

$\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}$ .....(1)

Given values:

$V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol$

Plugging values in equation 1:

$\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s$

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

<u>For B:</u>

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

$Rate\propto \frac{1}{\sqrt{M}}$

Where, M is the molar mass of the gas

Forming an equation for the two gases:

$\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}$ .....(2)

Given values:

$Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol$

Plugging values in equation 2:

$\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr$

Hence, the rate of effusion of $SO_2$ gas is $1.006\times 10^{-3}mol/hr$

8 0

2 years ago