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MArishka [77]
3 years ago
6

PLEASEEE HELPP!!! Select all the correct answers.

Chemistry
1 answer:
snow_lady [41]3 years ago
4 0

Answer: Compounds having the same empirical formula CH_2O are:

C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6

Explanation:

Empirical formula tells us about the proportion of the elements present in the compound but it do not tells us about the actual numbers of atoms of the elements present in the compound.

In given empirical formula CH_2O that is proportion of  C:H:O = 1:2:1

In C_2H_4O_2 the proportion of C:H:O =2:4:2= 1:2:1

In C_3H_6O_3 the proportion of C:H:O =3:6:3= 1:2:1

In CH_2O_2 the proportion of C:H:O =1:2:2= 1:2:2

In C_5H_{10}O_5 the proportion of C:H:O =5:10:5= 1:2:1

In C_6H_{12}O_6 the proportion of C:H:O =6:12:6= 1:2:1

Compounds having the given empirical formula CH_2O are:

C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6

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