Question

PLEASEEE HELPP!!! Select all the correct answers.

Answer 1

Answer: Compounds having the same empirical formula $CH_2O$ are:

$C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6$

Explanation:

Empirical formula tells us about the proportion of the elements present in the compound but it do not tells us about the actual numbers of atoms of the elements present in the compound.

In given empirical formula $CH_2O$ that is proportion of  C:H:O = 1:2:1

In $C_2H_4O_2$ the proportion of C:H:O =2:4:2= 1:2:1

In $C_3H_6O_3$ the proportion of C:H:O =3:6:3= 1:2:1

In $CH_2O_2$ the proportion of C:H:O =1:2:2= 1:2:2

In $C_5H_{10}O_5$ the proportion of C:H:O =5:10:5= 1:2:1

In $C_6H_{12}O_6$ the proportion of C:H:O =6:12:6= 1:2:1

Compounds having the given empirical formula $CH_2O$ are:

$C_2H_4O_2,C_3H_6O_3,C_5H_{10}O_5,C_6H_{12}O_6$