Answer:
101.2%
Explanation:
Given:
Theoretical yield of the precipitate = 0.914 g
Actual yield of the precipitate = 0.925 g
Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.
Framing in equation form, we have:
Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,
Therefore, the percent yield is 101.2%.
Answer:
Explanation:
Hello there!
In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:
Which must be balanced to accurately predict the mole ratio on the reactants side:
Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:
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