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jok3333 [9.3K]
3 years ago
9

Lexie bought a new car for $32,000. It

Mathematics
1 answer:
UNO [17]3 years ago
5 0
You just got to divide 32000 and make that number and get rid of the 19.6 percent of that number then you should get the answer
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What is the area of the rectangle<br> below?
DiKsa [7]

Answer:

Area of rectangle = l×b= 3 1/4 × 1 1/2

= 31/8 = 4 7/8

4 0
1 year ago
How do you get the equation of the line in fully simplified slope-intercept form?​
Igoryamba

Answer:

y= -2/5 x -4

Step-by-step explanation:

So the equation is y=mx+b. Where m=slope and b=y-intercept. To find b, you would see at what point does the line cross the y axis. That would be at -4 so, -4 would be the b or y-intercept. To find m, you would take two points on the line and use this equation:

m=(y2 - y1 )/(x2 - x1)

If you were using the points, (-10,0) and (0, -4) the equation would be:

m=(-4-0) / (0+10)

So, m= -2/5

The equation of the line would end up being:

y= -2/5 x -4

4 0
3 years ago
A plane takes off and climbs steadily gor 30 minutes until it reaches 35,000 feet. It travels at that altitude for 2 hours until
horrorfan [7]
This is a function where:
x - time in minutes;
y = f ( x ) - altitude of a plane in feet.
Max altitude = 35,000 feet
0.5 h + 2 h + 15 min = 30 min + 120 min + 15 min = 165 min
Domain:
x ∈ [ 0;  165 ]
Range:
y ∈ [ 0;  35,000 ]
6 0
3 years ago
Answer this please, actually only delany, have a heart she needs the points
MariettaO [177]

the answer is a B:9

Step-by-step explanation:

THE ANSWERS FOR u question is a B:9

5 0
3 years ago
Read 2 more answers
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
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