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bonufazy [111]
4 years ago
7

Expressions 4 tens + 6 tens in standard form

Mathematics
1 answer:
Ira Lisetskai [31]4 years ago
5 0
40+60=100
I hope this helps^^
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Please help me with number 41!!!!!!!!
olga2289 [7]
4y>12
y>12/4
y>3

5>3
6>3
7>3

Therefore, the solution is {5,6,7}
4 0
3 years ago
Directions: Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).. Th
Anuta_ua [19.1K]

Answer

Find out the The numerical value of A - B  and the numerical value of B - A .

To prove

As given

The expression 113.47 - (43.72 - 26.9) represents A.

The expression 113.47 - (26.9 - 43.72) represents B .

Thus

A - B =  113.47 - (43.72 - 26.9)  - ( 113.47 - (26.9 - 43.72))

First solving the bracket terms.

A - B =  113.47 - (43.72 - 26.9)  -  113.47  + (26.9 - 43.72)

        = 113.47 - 16.82 - 113.47 - 16.82

        =  113.47  - 113.47 - 16.82 - 16.82

        = -33.64

Therefore the value of A- B is -33.64 .

Thus

B - A = 113.47 - (26.9 - 43.72) - (113.47 - (43.72 - 26.9))

First solving the bracket terms.

B - A = 113.47 - (26.9 - 43.72) - 113.47 + (43.72 - 26.9)

        =  113.47 + 16.82 - 113.47 + 16.82

        = 33.64

Therefore the value of the A - B is -33.64 and B - A is 33.64 .

6 0
3 years ago
Read 2 more answers
If f(1) = 1 and f(n) = -3f(n-1) then find the value of f(5).
baherus [9]

Answer:

f(5)=-12

Step-by-step explanation:

f(5)=-3*f(5-1)

f(5)=-3*(4)

f(5)=-12

Hope this helps

8 0
3 years ago
Read 2 more answers
If a/b and c/d are rational expressions, then which of the following is true?
tatiyna
It’s al going to be true
4 0
3 years ago
The degree of the polynomial function f(x) is 3. The roots of the equation f(x)=0 are −4 , 0, and 2. Which graph could be the gr
KATRIN_1 [288]

We know that the polynomial function is of degree 3, and that its roots are -4, 0, 2.

With this data we can write a generic equation for the function:

f (x) = bx (x + 4) (x-2)

Since the function is of degree 3 and cuts the axis at x = 0, then it has rotational symmetry with respect to the origin.

The graph of the function can be of two main forms, based on the value of the coefficient b.

If b is positive then the function grows from y = -infinite and cuts the x-axis for the first time in -4. Then it decreases, cuts at x = 0 and begins to grow again cutting the x-axis for the third time at x = 2. and continues to grow until y = infnit


If b is negative, then the function decreases from y = infinity and cuts the x-axis for the first time in -4. Then it grows, cuts at x = 0 and begins to decrease again by cutting the x-axis for the third time at x = 2, and continues to decrease until y = -infnit.


In the attached images the graphs of the function f (x) are shown assuming b = -1 and b = 1

5 0
3 years ago
Read 2 more answers
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