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Kisachek [45]
3 years ago
8

Most Swiss starlings produce four to five eggs in each clutch. Those producing fewer or more than this have

Biology
1 answer:
photoshop1234 [79]3 years ago
7 0

Ans. (C). stabilizing selection.

Stabilizing selection is defined as a variant of natural selection that stabilizes a particular trait in a population on an average trait value (non-extreme trait value). It favors individuals with intermediate variants, instead of individuals having extreme traits.

The females, which lay 4-5 eggs in each clutch, are showing an average or intermediate trait, while the females, which produce fewer or more eggs than this are showing extreme traits. Hence, individuals with extreme traits will show reduced fitness due to stabilizing selection.  

Thus, the correct answer is option (C).

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Calculate the mass defect for oxygen-16 given this data. Round to the 5es001-1.jpg decimal place. mass of an oxygen-16 atom: 15.
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Answer:

Explanation:

Given parameters:

Mass of oxygen atom = 15.994914amu

Mass of a proton = 1.00728amu

Mass of a neutron = 1.00866amu

Unknown:

Mass defect = ?

From the periodic table, the number of the elementary particles in a neutral Oxygen atom is given below:

           Number of protons = 8

           Number of neutrons = 8

          Number of electrons = 8

Solution

The mass defect examines the difference between the actual mass of an atom and sum of masses of the nucleons.

The mass of an atom is concentrated in the nucleus which contains protons and neutrons. Electrons have little to no weight compared with the nucleons.

    To calculate the mass defect, we first know the mass of the nucleons first:

           1 proton has a mass of  1.00728amu

           8 protons will weigh: (8 x 1.00728)amu = 8.05824amu

For the neutrons:

          1 neutron has a mass of 1.00866amu

          8 neutrons will weigh: (8 x 1.00866)amu = 8.06928amu

Mass of the nucleons = mass of protons + mass of neutrons

                                   = 8.05824amu + 8.06928amu

                                   = 16.12752amu

The mass defect = mass of the nucleons - mass of the atom

                             = 16.12752amu - 15.994914amu

                              = 0.132606amu ≅ 0.13261amu to 5 decimal places

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