A chocolate wrapper is 6.7 cm long and 5.4 cm wide. Calculate its area up to

When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st

defon

Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

Power drawn by hairdryer is P = 1650 watt

We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So $1650=110\times I$

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0

4 years ago

What do YOU feel is the meaning of life?

Dominik [7]

Answer:

Meaning of life is to live it to your fullest

Explanation:

Yolo-You only live one

7 0

3 years ago

Lolz plz help me with this it’s due soon

White raven [17]

Answer:

Explanation:

c slowing down since the distance is going down and the time is moving up.

7 0

3 years ago

how much work did the movers do (horizontally) pushing a 41.0- kg crate 10.3 m across a rough floor without acceleration, if the

11111nata11111 [884]

W=2485.65 J ,work did the movers do friction force a 41.0- kg crate 10.3 m across a rough floor without acceleration

<h3>What is a basic friction force?</h3>

Two surfaces that come into contact and slide against one another produce a force known as frictional force. Several aspects that influence the frictional force include: The surface texture as well as the amount of force attracting them together have the most effects on these forces.

<h3>What outcomes does friction produce?</h3>

It generates heat, which is useful for warming our bodies or specific areas of any object. Power is also lost as a result. It makes noise during every operation. We are able to walk, run, dance, etc. due to friction.

To know more about friction force visit:

brainly.com/question/1389727

#SPJ4

7 0

1 year ago

A gardener pushes a 20 kg lawnmower whose handle is tilted up 37∘ above horizontal. The lawnmower's coefficient of rolling frict

e-lub [12.9K]

Answer:

58.4 W

Explanation:

The speed of the lawnmower is constant: this means that its acceleration is zero, so the net force on it is zero.

The equation of the forces along the two directions therefore are:

- Perpendicular to the floor: $F sin \theta + R -mg =0$

- Parallel to the floor: $F cos \theta - \mu R = 0$

where

F is the push of the gardener

R is the normal reaction

m = 20 kg is the mass

g = 9.8 m/s^2 is the acceleration of gravity

$\mu=0.18$ is the coefficient of friction

$\theta=37^{\circ}$

Solving for R,

$R=mg-Fsin \theta$

Substituting into the other equation,

$F cos \theta - \mu (mg-Fsin \theta) = 0\\F cos \theta - \mu mg + \mu F sin \theta = 0\\F(cos \theta+\mu sin \theta)=\mu mg\\F=\frac{\mu mg}{cos \theta + \mu sin \theta}=\frac{(0.18)(20)(9.8)}{cos 37^{\circ}+0.18(sin 37^{\circ})}=38.9 N$

And the power he must supply therefore is the product of this force and the speed:

$P=Fv=(38.9)(1.5)=58.4 W$

7 0

4 years ago