A chocolate wrapper is 6.7 cm long and 5.4 cm wide. Calculate its area up to
1 answer:
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Answer:
Time period of oscillation on moon will be equal to 3.347 sec
Explanation:
We have given mass which is attached to the spring m = 3.42 kg
Spring constant K = 12 N/m
We have to find the period of oscillation
Period of oscillation is equal to , here m is mass and K is spring constant
So period of oscillation
So time period of oscillation will be equal to 3.347 sec
As it is a spring mass system and from the relation we can see that time period is independent of g
So time period will be same on earth and moon
Answer:
17.1130952381 s
No
Explanation:
t = Time taken
u = Initial velocity = 115 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -6.72 m/s² (negative as it is decelerating)
From the equations of motion
The minimum time required to stop is 17.1130952381 s
The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.