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Leona [35]
2 years ago
12

A car was driving at a speed of 10 m/s. In 3 seconds, it accelerated to a speed of 50 m/s. Calculate the car's acceleration.

Physics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

\boxed {\boxed {\sf 13.3 \ m/s^2}}

Explanation:

Acceleration is the rate of change of velocity with respect to time. It is the change in velocity over the change in time, and it is calculated using the following formula.

a= \frac{ v_f-v_i}{t}

The car starts at a speed of 10 meters per second, then it accelerates to a speed of 50 meters per second. It achieves this acceleration in 3 seconds.

  • v_f= 50 m/s
  • v_i= 10 m/s
  • t= 3 s

Substitute the values into the formula.

a= \frac{50 \ m/s - 10 \ m/s}{3 \ s}

Solve the numerator.

  • 50 m/s -10 m/s= 40 m/s

a= \frac{40 \ m/s}{3 \ s}

Divide.

a= 13.3333333 \ m/s/s

a \approx 13.3 \ m/s^2

The car's acceleration is approximately <u>13.3 meters per second squared.</u>

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san4es73 [151]

Answer:

Explanation:

If Ig be moment of inertia about an axis through centre of mass and I be moment of inertia through any other axis parallel to earlier axis , then according to theory of parallel axis ,

I = Ig + Md²

where M is mass of the body and d is distance between two parallel axis.

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4 0
3 years ago
a missile is moving 1810 m/s at a 20.0. It needs to hit a target 29,500m away in a 65.0 magnitude in 9.20s. What acceleration mu
Vesna [10]

Answer:

323 m/s²

Explanation:

Given:

x₀ = 0 m

y₀ = 0 m

x = 29500 cos 65°

y = 29500 sin 65°

v₀x = 1810 cos 20°

v₀y = 1810 sin 20°

t = 9.20

Find:

ax, ay, θ

First, in the x direction:

x = x₀ + v₀ t + ½ at²

29500 cos 32° = 0 + (1810 cos 20°) (9.20) + ½ ax (9.20)²

25017 = 15648 + 42.32 ax

ax ≈ 221.4

And in the y direction:

y = y₀ + v₀ t + ½ at²

29500 sin 32° = 0 + (1810 sin 20°) (9.20) + ½ ay (9.20)²

15633 = 5695 + 42.32 ay

ay ≈ 234.8

Therefore, the magnitude of the acceleration is:

a² = ax² + ay²

a² = (221.4)² + (234.8)²

a ≈ 322.7

Rounded to 3 significant figures, the magnitude of the acceleration is approximately 323 m/s².

7 0
3 years ago
The driver or a sports car traveling at 10 m/s steps down hard on the accelerator for 5 seconds. If they accelerate at a rate of
ivanzaharov [21]

Answer:

53.125m

Explanation:

The displacement of the car, denoted by S, can be calculated using the formula:

S = ut + 1/2at²

Where;

u = initial velocity/speed (m/s)

t = time (s)

a = acceleration (m/s²)

According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?

S = ut + 1/2at²

S = (10 × 5) + 1/2 (0.25 × 5²)

S = 50 + 1/2 (0.25 × 25)

S = 50 + 1/2(6.25)

S = 50 + 3.125

S = 53.125m

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