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jek_recluse [69]
2 years ago
9

The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. what is the a

ngular frequency for this motion?
Physics
1 answer:
bulgar [2K]2 years ago
6 0

The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

To know more about the "general equation of SHM", refer to the link below:

brainly.com/question/14869852?referrer=searchResults

#SPJ4

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Answer:

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Explanation:

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we subtitle the friction coefficient value

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               6.825  \frac{d}{d_o} = 11.74

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