Surface area for this 4height 4lenght 6 width
1 answer:
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Answer:
Reactive power is 1.152 VARs
Step-by-step explanation:
We are given that in a parallel circuit,,R=47kΩ and
=50kΩ.
reactive power means the dissipating power resulting from inductive and capacitive loads measured in volt-amperes reactive(VAR).Since our circuit has inductor only, reactive power will be power dissipated from inductor.
Current through inductor=milli amps=0.0048 A
Reactive power = (current flowing through inductor)X (Voltage across inductor)
Hence reactive power = 0.0048 X 240=1.152 VARs
Remember
translates to 
and
so
4096=16^3
divide both sides by 3
translate
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6
and
so
4096=16^3
divide both sides by 3
translate
3x-2=16
add 2 to both sides
3x=18
divide both sides by 3
x=6
Answer:
(4,1)
Step-by-step explanation:
The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).
To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.
To find the y-coordinate, input the x=4 and solve for y.
The vertex is (4,1).