Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = 
=1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
= 
Answer:
4/5x + y = -2
Step-by-step explanation:
We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.
This is the problem from combination.
The formula for combination is given by
Here, n= 11, r= 3
Therefore, total number of ways is given by
A is the correct option.
The decrease is (95-68) = 27 .
As a fraction, the decrease is 27/95 of the original amount.
To change any fraction to a decimal, do the division:
(27) divided by (95) = 0.2842...
To change any decimal to a percentage, move the
decimal point two places that ==> way:
0.2842... = 28.42... %
